A 2 ft F, 4 ft M B. - 3 ft- 30 -x F,

42 in 64 [in]- 50 in D 59 in B این دو سال است اند اما او شده از این سامانه 63 in -10 in 21 in ( Given: The plate( The shaded rectangular volume) has weighs 240 lbf. It is. suspended bycable CD, Which D is wall anchor. So, Find the magnitude of force in the cable CD such the system is in static equilibrium??. Show all works.

Show the correct FBD please. The answer must be TA=TB=20.4 lb, TC=27.2 lb

show FBD

Express:            50000mm3 as m3 3.5m3 as mm3 20m3 as cm3 45cm3 as m3

- once answered Correctly will UPVOTE!!

Exercises: find the solutions of: y² + y = - 6x Ô ý - y = 2x (2sinx ty cosx) 8 ⑨-'=x lo y" + y² - 4 y²- 4y = 32 ³² - 4x-6. -3x

1. a – 125mm 20mm 20mm 100mm 20mm 80mm For the figure given above, calculate the neutral axis and also find the second moment of inertia.

The horizontal component of Force F1 (unit is in N), H1= The vertical component of Force F1 (unit is in N), V1 = The horizontal component of Force F2 (unit is in N), H2= The vertical component of Force F2 (unit is in N), V2 = The horizontal component of Force F3 (unit is in N), H3= The vertical component of Force F3 (unit is in N), V3 = The vertical component of Force F4 (unit is in N), V4 = The horizontal component of Force F5 (unit is in N), H5= The vertical component of Force F5 (unit is in N), V5 = The horizontal component of Force F6 (unit is in N), H6= The vertical component of Force F6 (unit is in N), V6 = The sum of horizontal force component for the given system (unit is in N),begin inline style sum for H of end style = The sum of vertical force component for the given system (unit is in N),begin inline style sum for V of end style = The resultant of the given force system is (unit in N), R = The direction of Resultant Force is = Short Answer question