Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Current Division Method
The generalized current divider formula is given by the following relation below,
Question

Subject: Engineering Utilities

Please see tha image attached for the problems.

Assume that 1. Ia=10A and 3. Ia=100A

 

Activity no. 14. DC Motors Problem Solving. 1. Determine the back emf and the torque developed for a 4-pole motor with 4 armature paths, 4800 conductors, flux per pole of 4.2 x 10° lines, running at a speed of 60 rpm. 2. The output torque of a dc motor, running at a speed of 250o rpm, is 120 Nm. If the output power is 2,918 W, calculate the rotational loss. 3. Ad.s motor develops a back emf of 458 V. The machine has 6-poles and the armature is lap- connected with a64 conductors. The flux per pole is 0.05 WB. Calculate (i), the speed and (ii) the gross torque developed by the armature.
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Transcribed Image Text:Activity no. 14. DC Motors Problem Solving. 1. Determine the back emf and the torque developed for a 4-pole motor with 4 armature paths, 4800 conductors, flux per pole of 4.2 x 10° lines, running at a speed of 60 rpm. 2. The output torque of a dc motor, running at a speed of 250o rpm, is 120 Nm. If the output power is 2,918 W, calculate the rotational loss. 3. Ad.s motor develops a back emf of 458 V. The machine has 6-poles and the armature is lap- connected with a64 conductors. The flux per pole is 0.05 WB. Calculate (i), the speed and (ii) the gross torque developed by the armature.
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