Active ingredient (PRODUCT) Potassium acetate Raw Materials Actual Yield Formulation Dosage Form Packaging (REACTANTS) 2 kg acetic acid and 1.5 kg potassium bicarbonate 1.33 kgs Potassium Ācectate 1100 mg per 5 mL Oral Solution 473 mL per bottle BALANCED EQUATION: CH;COOH + KHCO; → CH;COOK + CO2 + H2O With the given information, solve for the following: A. Mass to mass stoichiometry calculation B. Amount (g) in excess C. Percent yield Number of dosage form and packaging that can be produced from stoichiometric calculation

Active ingredient (PRODUCT) Potassium acetate Raw Materials Actual Yield Formulation Dosage Form Packaging (REACTANTS) 2 kg acetic acid and 1.5 kg potassium bicarbonate 1.33 kgs Potassium Ācectate 1100 mg per 5 mL Oral Solution 473 mL per bottle BALANCED EQUATION: CH;COOH + KHCO; → CH;COOK + CO2 + H2O With the given information, solve for the following: A. Mass to mass stoichiometry calculation B. Amount (g) in excess C. Percent yield Number of dosage form and packaging that can be produced from stoichiometric calculation

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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1 of 4 Watch the video that shows using the dilution method to make a solution of known concentration. Note that while the video shows the use of a beaker, in the lab we typically use a volumetric flask to make the diluted solution. The stock solution of KMNO, has a concentration of 2.6 x 10ª M. The pipette has a volume of 10.0 mL. What is the amount of KMNO. delivered to the solution, in moles? mol Submit When using the dilution method to prepare a solution of known concentration, remember that the total amount of solute is the same in both the measured volume of the more concentrated stock solution and in the dilute solution created. This means we can use a simple ennation (Emation 4 2) to calculate the volume or concentration of either the stock solution or the more dilute solution Fauation 4 2 is stv hulu W
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2) Calculate the volume (in mL) of 0.100 M Na2Co3 needed to produce 1.00 g of CaCo3 (s). There is an excess of CaCl2. Molar Mass of calcium carbonate = 100.09 g/mol
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Fe3+ + Cr2O72- → Fe2+ + Cr3+. Cr2O72- + ClO2- → Cr3+ + ClO2. Fe3+ + ClO2- → Fe2+ + ClO2. No reaction.
Show all pertinent solutions. Expree your final answers up to fourth decimal places. 1. In the preparation of aspirin, 6.0 grams of salicylic acid was made to react with acetic acid anhydride forming 4 grams of aspirin. Calculate the % yield of aspirin. 2. Calculate the amount of sodium sakt of aspirin obtained from the preparation
Masses : Ca = 40.08 g S= 32.07 g O= 16.00 g A 35.0 mL sample of CaSO4 was evaporated to dryness, leaving 0.967 g of residue. What was the molarity of the original solution? step by step please
* 0 il * CE Previous Page 4 of 9 Mass = 12 S Next → g S CHAPTER 4-STOICHIOMETRY: QUANTITATIVE INFOR S What mass of oxalic acid, H₂C2O4? H₂C2O4, is required to prepare 100. mL of a solution that has a concentration of 0.40 M alı 4 C Document3.docx C RESEA C
Calibri в IUA 10 1 2 5 6 For each word equation, write the correct skeleton equation, and then balance it to form a chemical equation. (5К/5A) a. copper(I) oxide hydrogen gas + copper water + skeleton - balanced equation b. lead(II) nitrate potassium iodide lead(II) iodide potassium nitrate + skeleton - balanced equation étv MAY 9. MacBook Pro !!!
Name: Section: Report Sheet (Data must be recorded directly in pen) Write the balanced chemical equation for the reaction of copper (II) sulfate and aluminum 3 CuSO4 + 2Al(s) → 1 Al₂(SO4) = (aq) + 3 Cu (s) DETERMINE THE LIMITING REACTANT. Show your calculations of starred items on next page Volume of CuSO4: 50.0 mL. 0.0500 L Molarity of CuSO4 used: 1.00 "Moles of CuSO4 used: 0.0500 0.0500 "Moles of copper produced based on CuSO, used: Molar mass of copper: *Grams of copper produced based on CuSO4 used: Mass of aluminum used Molar mass of aluminum "Moles of aluminum used: "Moles of copper produced based on Al used: Molar mass of copper: *Grams of copper produced based on Al used: Aluminum Limiting Reagent: Theoretical Yield: Actual Yield: "Percent Yield: g Cu Date: g Cu % yield Cu 63.546 318 0.759 26.982 - M CuSO4 moles CuSO moles Cu g/mol Cu(Periodic Table) g Cu g Al g/mole Al Pericdit Table D. 0281 moles of Al 0.0422 moles Cu 63.546 g/mol Cu (periodic table) 2.48 g Cu