Acetone and isopropyl alcohol are generally not suitable for use in extraction, but are frequently used as recrystallization solvents. Explain
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Acetone and isopropyl alcohol are generally not suitable for use in extraction, but are frequently used as recrystallization solvents. Explain
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- 0.750 g of crude acetylsalicylic acid is recrystallized using ethanol as the solvent. The solubility of acetylsalicylic acid in ethanol at 78 oC is 15.45 g per 100 mL. a) How much hot ethanol is needed to dissolve the 0.750 g of acetylsalicylic acid? b) If the solubility of acetylsalicylic acid at 25 oC is 0.100 g per 100 mL, how much acetylsalicylic acid will be obtained after crystallization in ethanol at 25 oC? Use the volume from part A. c) What is the maximum percent recovery for this re-crystallization105 100 95 75 0 1 2 3 4 5 67 8 9 10 11 12 13 14 15 16 17 18 19 20 Volume distillate collected (mL) 1. Indicate the volume of the distillate at which you should stop collecting to make sure that the distillate is only composed of one component. 2. Indicate the boiling point range involved in the collection of this amount of distillate. Temp in Still Head ("C)The boiling points for the compounds are 118 °C and 35 °C respectively. The solubility for both compounds is the same (8g/100g water). Explain this observation for (i) boiling point disparity; (ii) solubility similarity H-bonds form in diethyl ether; n-butyl alcohol forms H-bonds in water H-bonds form in n-butyl alcohol; diethyl ether forms H-bonds in water H-bonds in n-butyl alcohol; Both compounds form H-bonds in water O Both compounds form H-bonds; Both compounds form H-bonds in water
- 4. what makes acetone miscible with water?5. what makes ethyl acetate immiscible with water?1. What boiling point of the following mixture of compounds. Then, which would boil first? And Finally, indicate what type of distillation will you use to separate them.4. CH₂ -NH, Circle the pairs of organic solids which can be separated from each other by solvent extraction using 2M HCI.* CH₂ CH H.C-C-CH-C-CH CH CH H3C- H.C acid + acid → no reaction base + base → no reaction CH₂ -CH₂ -COOH -COOH CH HC-С-СООН CH₂ сну CH H₂C-C-COOH CH -COOH H.C. H.C- b09) 0) YBW 2 CH₂ ht of -сҢ CH3 H.C-С-соон сна ондул -NH₂ 75 0 986 CH CH -COOH -NH₂