According to this law, force of attraction from larger on smaller mass is r m M O Equal to the force from smaller mass on larger mass O Larger than the force from smaller mass on larger mass There is no information to answer this question O Smaller than the force from smaller mass on larger mass

When the Moon is directly overhead at sunset, the force by Earth on the Moon, FEM, is essentially at 90° to the force by the Sun on the Moon, FSM, as shown below. FEM=1.98×10^20N and FSM=4.36×10^20N, all other forces on the Moon are negligible, and the mass of the Moon is 7.35×10^22kg. 1. Write an expression for the magnitude of the acceleration of the Moon.   2. What is the acceleration of the Moon in m/s^2?

Extra: You have two disks lying flat on ice, one has a string wrapped around the outside edge which unravels as you pull, the other has a string attached to a peg in the center. The discs have equal masses and dimensions and are initially at rest. If you start pulling both strings at the same time with the same constant force, at some time t later which of the two disks has moved further? Or have they both moved the same distance? Explain.

While doing an experiment a student uses a triple beam balance to measure the mass of a cart and gets 273.9 g. While calculating the mass they get the values: 268.5 g. 288.7 g, and 270 g. What would the GAV for the cart be? 268.5 g 288.7 g 275.7 g 274.8 g 273.9 g

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We will use differential equations to model the orbits and locations of Earth, Mars, and the spacecraft using Newton’s two laws mentioned above. Newton’s second law of motion in vector form is: F^→=ma^→ (1) where F^→ is the force vector in N (Newtons), and a^→ is the acceleration vector in m/s^2,and m is the mass in kg. Newton’s law of gravitation in vector form is: F^→=GMm/lr^→l*r^→/lr^→l where G=6.67x10^-11 m^3/s^2*kg is the universal gravitational constant, M is the mass of the larger object (the Sun), and is 2x10^30 kg, and m is the mass the smaller one (the planets or the spacecraft). The vector r^→ is the vector connecting the Sun to the orbiting objects. Step one ) The motion force in Equation(1), and the gravitational force in Equation(2) are equal. Equate the right hand sides of equations (1) and (2), and cancel the common factor on the left and right sides. Answer: f^→=ma^→        f=Gmm/lr^→l^2         a^→=Gmm/lr^→l^2 x r^→/lr^→l        r^→=r^→/lr^→l * Gmm Could you please…

At a particular instant, in a coordinate frame chosen by us, the Earth (mass = 6 x 1024 kg) is at location (-7.30 × 106, -7.80 × 106, 3.73 × 106) m and the Moon (mass = 7 x 10²² kg) is at location (-1.35 × 108, -2.50 × 10³, 2.82 × 108) m. A satellite with mass 5000 kg is at location (-1.18 × 10³, -2.73 × 10³, 3.10 × 108) m. What is the net force on the satellite? Assume that the gravitional force of the Sun is negligible. net = i i !)N

The force F acting on a body with mass m and velocity v is the rate of change of momentum: F = (d/dt)(mv). If m is constant, this becomes F = ma, where a = dv/dt is the acceleration. But in the theory of relativity the mass of a particle varies with v as follows: m= mo/NT- v/c², where mo is the mass of the particle at rest and c is the speed of light. Show that moa F = (1 – v*/c*)/²

Let's say we have a M1 and M2. Let's just say. Let's examine this hypothetical situation. The first mass would be 1.50 kg and the second mass would be 2.00 kg. These two masses would then be separated by a length or we should say a distance of this L = 2.50 m. Let's say we want to place a third mass (immaterial mass) in the middle of the two masses, such that there would be no net force. Find this specific place where this would occur, and to make it easy, find the distance from the first mass towards this third mass

Two objects, m1 and m2 are gravitationally attracted to one another. However, m1 is 500 times more massive than m2. Which mass experiences the greater gravitational attractive pull force?   A) mass m1 experiences a greater attractive force from m2 B) mass m2 experiences a greater attractive force from m1 C) both masses experience equal but opposite attractive forces D) the problem statement does not provide enough information to be solved