### Sleepwalking Study: Proportion Hypothesis TestAccording to a reputable magazine, 35% of people in a certain large country have sleepwalked at least once in their lives. Suppose a random sample of 200 people showed that 48 reported sleepwalking. The null and alternative hypotheses for a test that would test whether the proportion of people who have sleepwalked is 0.35 are \( H_0: p = 0.35 \) and \( H_A: p \neq 0.35 \), respectively. The conditions for such a test are satisfied. Use the technology output provided to determine the test statistic and p-value for the test, and provide a conclusion. Use a significance level of 0.05.#### Hypothesis Test Details:1. **Determine the Test Statistic**: \( z = \) (Round to two decimal places as needed)2. **Determine the p-value**: \( \text{p-value} = \) (Round to three decimal places as needed)3. **Conclusion**: What is the conclusion to this test? [Dropdown] \( H_0 \) [Dropdown] sufficient evidence to conclude that the proportion of people who have sleepwalked [Dropdown] 0.35.#### Technology OutputThe technology output provides the following results:- **Hypothesis Test Results**: - \( p \): Proportion of successes - \( H_0: p = 0.35 \) - \( H_A: p \neq 0.35 \)- **Data**: - Proportion Count: 48 - Total Sample: 200 - Sample Proportion: 0.24 - Standard Error (Std. Err.): 0.03372684 - Z-Statistic (Z-Stat.): -3.2614970 - P-value: 0.0011Use this information to complete the hypothesis test.

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According to a reputable magazine, 35% of people in a certain large country have sleepwalked at least once in their lives. Suppose a random sample of 200 people showed that 48 reported sleepwalking The null and alternative hypotheses for a test that would test whether the proportion of people who have sleepwalked is 0.35 are Ho p=0 35 and H, p# 0.35, respectively. The conditions for such a test are satisfied Use the technology output provided to determine the test statistic and p-value for the test, and provide a conclusion. Use a significance level of 0.05 Click the icon to view the technology output Determine the test statistic Z= (Round to two decimal places as needed) Determine the p-value p-value = (Round to three decimal places as needed.) !! What is the conclusion to this test? 0.35. Ho There sufficient evidence to conclude that the proportion of people who have sleepwalked

According to a reputable magazine, 35% of people in a certain large country have sleepwalked at least once in their lives. Suppose a random sample of 200 people showed that 48 reported sleepwalking The null and alternative hypotheses for a test that would test whether the proportion of people who have sleepwalked is 0.35 are Ho p=0 35 and H, p# 0.35, respectively. The conditions for such a test are satisfied Use the technology output provided to determine the test statistic and p-value for the test, and provide a conclusion. Use a significance level of 0.05 Click the icon to view the technology output Determine the test statistic Z= (Round to two decimal places as needed) Determine the p-value p-value = (Round to three decimal places as needed.) !! What is the conclusion to this test? 0.35. Ho There sufficient evidence to conclude that the proportion of people who have sleepwalked

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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