(A,B,C,D,E,F,G,H.I.J) 5jäi a Sta. B.S I.F.S F.S H.I Ground Elev. 30+25 A 13.728 12.523 30+50 12.371 30+75 1.550 C Т.Р 0.964 1.452 D 12.276 31+00 E 12.035 31+25 12.140 31+50 0.905 31+75 H. 12.490 32+00 32+25 0.521 I J 12.758

Q: Student No. 1 Line S-1 Line S-2 S-3 S-4 Student No. 2 S-1 S-2 S-3 S-4 Direction (deg-min-sec) Angle…

A: Given : Direction of station in Quadrantal system.

Q: 6T 5T 2T 3T 3m 1 13 14 35 15 2,5 9 D 10 H 12 K 2,5 m 2,5 m 2,5 t 2,5 m

A: Given truss:

Q: Finding Reachon fa VAt Vy = 34+(60(442.7)+ fx6x 18 =490KN. %3D Y*9.7= 5778+91.8+1346-7 らこ 207.87…

A:

Q: Line Distance AB BC CD DE EF FG 62.56 29.49 65.07 41.14 43.70 26.74 Forward Bearing N 81-02-05 W N…

A: Given: LINE FB BB AB N 81-02-05 W S 79-26-30 E BC N 08-16-07 W S 13-18-15 E CD S 87-34-45 E…

Q: 520 NA 230 N/m Chinged -13m 6m- BO -15m- 46 N O 6774 N D 3175 N 2450 N

A:

Q: if P=140 N and a=4m and b=2m and tetta= 33.7   find  F(EC) , F(ED), F(AB),F(AD)

A: Given  P=140 N and a=4m and b=2m and tetta= 33.7

Q: STATION B.S. F.S. ELEV. (m) BM1 9.08 150 BM1 9.08 TP1-L 12.24 3.73 ΤΡ1-Η 10.10 1.60 TP2-L 11.04 2.21…

A: Given data in question  Back sight  Fore sight  Elevation of BM To find out  Elevations Note I have…

Q: A. 103 391 D 110 75m 1.) DEPARTURE LUNE EA? 2.) INTERIO R ANGLE DEBC 7 3)BEARING OF AB? 4.) LATITUDE…

A: Since we know that departure of line EA = LEAsinθ…

Q: lim (z,y) (1,1) 22 - ry- y? 12 – y?

A:

Q: -300 200 4S 30k 30 30 E =? Ey=? Y. E,=? Eg=? Bq =? つ V.

A: Strain is given in different orientation 1st we have to resolve these into x and y direction.

Q: IBS) 3.45 (FS) BM-I (Elev 568.75 m) L.28 (BS) 3,32 TP- L85 (BS) 479 (FS) 92 FS) (Bs) TP-2 2.09 (FS)…

A: Prepare and complete the differential level notes for the information shown

Q: Oy =20 kN Txy E-25 kN Oy =20KN Ox =10kN 01 45 degree =-25 kN Oy =20 kN

A:

Q: 9AN 105 N 10.5 AN 5.7 kN D. 5.7 AN 24m 3.8 m 3.2 m 3.2 m 1.5 3.9 m 2. Answers: AB = 47.2 kN C; AC =…

A: Taking moments about A, we get

Q: LINE LAT DEP DPD 2A 1-2 -310.95 469.84 a 2-3 112.87 d -142,954.36 3-4 28.8 -1099.62 e f 4-5 -21.86 h…

A: DPD of a line = DPD of previous line + Lattitude of previous line + Lattitude of present line.   2A…

Q: roblem 1 : Given the following the differential level notes: STA Backsight (BS),m Ht. of Inst. (HI),…

A: Height of instrument when Back sighting BM-A:            Height of instrument = Elevation of MB-A…

Q: 20kn/m 37.784480 A 11.336k 3m 16.25kn/m 16.25km • A B G ↓ ↓ ↓ ↓ 326126 sm →→2 43,049kn 48.5297kn…

A:

Q: DPD Method Course ADJ. LAT ADJ. DEP DPD 2A АВ 69.92 -97.22 BC 57.14 82.10 CD -68.99 67.12 DA -58.07…

A:

Q: = 1000 N (C) FDe = 800 N (T) FDC FCE = 900 N (C) FCв 3D 800 N (T) %3D D -600 N 1000 N 36.87° 4 m E…

A:

Q: Problem 2 Line Distance 288425 AB BC CD DE EF FG GH 63.01 32.10 57.03 31.84 51.54 27.08 77.55…

A: We know that, Fore bearing- Back bearing =180°

Q: Läveling. Rod LLeveling Rod 3.90 Hla 0.35 (FS) BM 968 HI, 78s) 3,75 HI, 3.73 1.64 (FS) (8S) 0.98 Hl2…

A:

Q: SOON - 2m 450 N 10m 1.01 (d)

A:

Q: Use the virtual work method to determine the vertical deflection at joint C of the truss shown in…

A: Due to the complexity of the question i am giving handwritten solution

Q: 4. TITI 10' 20 kips 10' 1 max = Ama Max =

A: Given data:-

Q: F: 300 N 60 120 4S 45' F: S00N F: F, (-cos bo sin 45 i cos bocos 4sjt sin l6ok)

A: first of all take components on X-axis and note take negative sign when force component showing…

Q: Exercise For Practice 924 $12 30 50 FV X

A: Isometric Projection: Isometric Projection is a type of pictorial projection in which the three…

Q: ACTIVIJ', 200N Me 0.20 30N sの3e REA'O: a, T, ¿ Tz ム。

A:

Q: STATION H.I H. ANGLE H. DIST V. DIST ELEV. ft ft ft Instrument station #1 (between BM and station…

A: Height of the instrument =elevation +vertical height and   elevation =height  of indtrument -vetical…

Q: PI Elev 108.00m 1.50m -3% +6% 8.00m A Sta 1+060 PT PC Sta 1+000 Elev 100.00m

A: The length of the curve is generally referred to as the limit of the total sum of the line segment…

Q: J.74 3.45 (FS) GATEAT BM-1 Elev 568.75m) 1.28 BS) 3.32 (FS) TP- 1.85 (BS) 479 FS) 3.92 FS) 785) TP-2…

A: to compete the differential level notes.  figure given in the question can be considered as FBD

Q: omplete the table of information and calculate the difference in elevation of ation 0+ 020 and…

A: HERE BS FS AND IS ARE GIVEN .RL IS ALSO GIVEN THATS IS 200

Q: Draw the influence line for the force in member TC of the Baltimore truss.

A: ILD is the graphical representation of shear force, bending moment, deflection etc. under the effect…

Q: Line Length Pg Up Pg Dn 44 Observed magnetic azimuth Computed magnetic beaning Backward Forward…

A:

Q: Ship A left a Port at 12:00 noon and sails N 42°18' E at a rate of 3 mph. At 2:00 PM, ship B starts…

A:

Q: Finding Reachon faces wing eguilibrium equations'- VA+ V = 34+(60X4427)+ tx 6x 18 = 490KN- EM=0, x…

A: Given :

Q: 0.8 m 643m 15 AN C LOM D VN 120

A: Given Data:UDL=6kN/mConcentrated Load = 15kNSpan =3m

Q: 12.find interval normal moment

A: in above structure there are two hinge joint at S1 and S2 location. as we know, hinge releases all…

Q: BACKSIGHT FORESIGHT DE im) ELEVATION (m) STA RR (m) VD (m) RR (m) VD (m) (m) (m) BM- I01.245-4° 25'…

A:

Q: KE = 12,000J %3D m = 40kg

A:

Q: 0 (115) Now 20kip D MB = -2835.67 kipft чок р Hinge З кір JE UNDO, CLAPEP SP с 50kip 20 кір B 264.3…

A:

Q: Puzuo lew Pu= 40 kN KN.m Iime-45 min only (7005-750) Daton 2.5 7-0m f= f=420MPar we use 10 stirrpsr…

A: Solution:-  Shear force in the section Vu=Wu×L2  =12×50×6+40+40     =215 KN Shear force with…

Q: Line Distance 62.56 29.49 65.07 AB BC CD DE EF FG 41.14 43.70 26.74 Forward Bearing N 81-02-05 W N…

A: Given Data: The forward bearing and back bearing of the lines AB, BC, CD, DE, EF, and FG are given.…

Q: CE - 4510 HOMEVNORIK # O 40" 1) tes - SO00 psi CHECK Asmn & Et >0.005 FIND Mn 下 3° z8.s" 27 6-#10

A:

Q: Situation 5. Determine Ix amd ly 12" 6" 12" r=D4" r=6" 49

A:

Q: V= = 18.97 kd/m3 ko=0.25 %3D 8- 4898; ko = r-18.54G kA/ms1 ko-0 29 1:5m 8 =45.04 379k/m3. V= 18.121…

A:

Q: Qu Given d.(o.00l,0.05,0.3) (n ,Tizóc. Requened herght Capillarg Eise for water at 2oc, T5…

A: Using formula for capillary rise

Q: LINE, ****** LAT ****** DEP AB ****** 19.77 ****** 11.88 BC ****** 17.33 ****** -16.6 CD ******…

A: In a closed traverse sum of latitudes and departures is zero

Q: 10. Determine Ma when As'= 2,027 mm², As = 4,054 mm? Note: fek = 24 MPa, fy = 400 MPa, ē = 0.85B,…

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: El. ? El. 90 m El. 90 m 300m - 450 mm f = 0.03 F El. 80 m A 600m - 600 mm f = 0.025 E 300m - 450 mm…

A:

Q: earing or Azimuth of Line AB: 16710' Sta Observed Interior Angle 0 Adjusted Interior Sta Dist Мean…

A: Given:   Required to find:

Q: Find head (H) if ho =1400 cm, hi=300 cm,hdi=0.17m, hdo=0.02m ? Select one: O a. 10.15 m O b. 11.15 m…

A: Inlet: hi=1400 cm=14 m, hdi=0.17 m, Outlet: ho=300 cm=3 m, hdo=0.02 m.

British Gravitational Bg System Of Units

Measuring is the comparison of a particular physical quantity with its reference value. A unit is a fixed physical quantity. The length is a physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with.