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- (+) = + AB 71 KN or 0.672 → (+) √821/ or 35.71 KN (T) =D 1.20 +35.71821 - AC-0 10. 93 км от чаязки (с) 40 kv T 30sin 29.25 Assignment Members E BC Best starting J. for BE, CE & CE is al joint E. Moday Read al Support Reactions b) Member Forces

- (+) = + AB 71 KN or 0.672 → (+) √821/ or 35.71 KN (T) =D 1.20 +35.71821 - AC-0 10. 93 км от чаязки (с) 40 kv T 30sin 29.25 Assignment Members E BC Best starting J. for BE, CE & CE is al joint E. Moday Read al Support Reactions b) Member Forces

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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ANSWER ONLY THE RED BOX.

Method of Joints - Starting pt. must be having 2 members only Jt. D.. 13 821 200 1.30 Hinge 0.728 yom 20 2.25 40 cos 29.25 PODCA TINK 40517 29.25 A. Trusses 2040529-25 Ch Midterms Analysis of Structures 305m 29.25. ZFh=of → (+) 1.30 13 250 *1.20m +40 Sın 29-25=0 12 BD = + 22.40 KN or 22.40 (T) ZFy=o| (+ 0.728 -40 Cos 29.25-22-40 13√21+ DE=0 250 DE = + 45.84 KN or 45.84 KN (C) = 1 reaction 10.672 Method of Joints (for Determinate structures only) + 120m = 2 reactions 30605291250 11.40 -6,672 1.30m 40 60529.25 20sin 29.25 1.40m E 20 kil RE Jt. A: → 40 sin 29.25 2015 29.25 1821 1.20 ZFy=s) † (+) - 20 cos 29.25 + AB 30 KN 0.672 6 | 25√821 AB=35.71 KN or 35.71 KN (T) ΣFh=0] → (+) 20 Sin 29.25+ 35.71 10.672 B SC ÁC = + 46.93 KN or 40.93 KN (C) Check for Determinacy mrr = 2) 7 +(2+1) = 2 (5) 10 = 10 1.20 43 1.30m Cv ZM₁ = 0) 2 (+) -20 cos 29.25(1.20) + 30 Sin 29:25 (0.672m) + 40 Sin 29.25 (140) +40 Cos29.25(130) - RE (1.30) RE=147.42KN or 47.42 KN ans 2.50 AC !! 40 kw 1.40 =D E - AC-0 Jt. B 30sin 29.25 Ratio & Prop 140 Assignment Members BE BC 1.40m Sol'n: Read: al Support Reactions b) Member Forces 20 30 Cos 29.25 2.50 1.20 y = 0.672m 30 Best starting J. for BE, CE & CE is at joint E. Monday Cosa 40 2.50m SOH CAHTOA Jan 6 = 1.40 2:50 = 29.25 ZFy=0] ↑ (+) - 20 Cos 29.25-30 cos 29.25 -40 605 29.25 = 0 + Cv + 47.42 (BD Cv = 131·10 KN or 31·10 ²1 ans. знька 20 2 1.45m ΣFh=0] → (+) - Ch + Zo sin 29.25 + 30 sin 29.25+ 40 Sin 29.25 = 0 ch=143.98 kW or 43.98* K Clos
Transcribed Image Text:Method of Joints - Starting pt. must be having 2 members only Jt. D.. 13 821 200 1.30 Hinge 0.728 yom 20 2.25 40 cos 29.25 PODCA TINK 40517 29.25 A. Trusses 2040529-25 Ch Midterms Analysis of Structures 305m 29.25. ZFh=of → (+) 1.30 13 250 *1.20m +40 Sın 29-25=0 12 BD = + 22.40 KN or 22.40 (T) ZFy=o| (+ 0.728 -40 Cos 29.25-22-40 13√21+ DE=0 250 DE = + 45.84 KN or 45.84 KN (C) = 1 reaction 10.672 Method of Joints (for Determinate structures only) + 120m = 2 reactions 30605291250 11.40 -6,672 1.30m 40 60529.25 20sin 29.25 1.40m E 20 kil RE Jt. A: → 40 sin 29.25 2015 29.25 1821 1.20 ZFy=s) † (+) - 20 cos 29.25 + AB 30 KN 0.672 6 | 25√821 AB=35.71 KN or 35.71 KN (T) ΣFh=0] → (+) 20 Sin 29.25+ 35.71 10.672 B SC ÁC = + 46.93 KN or 40.93 KN (C) Check for Determinacy mrr = 2) 7 +(2+1) = 2 (5) 10 = 10 1.20 43 1.30m Cv ZM₁ = 0) 2 (+) -20 cos 29.25(1.20) + 30 Sin 29:25 (0.672m) + 40 Sin 29.25 (140) +40 Cos29.25(130) - RE (1.30) RE=147.42KN or 47.42 KN ans 2.50 AC !! 40 kw 1.40 =D E - AC-0 Jt. B 30sin 29.25 Ratio & Prop 140 Assignment Members BE BC 1.40m Sol'n: Read: al Support Reactions b) Member Forces 20 30 Cos 29.25 2.50 1.20 y = 0.672m 30 Best starting J. for BE, CE & CE is at joint E. Monday Cosa 40 2.50m SOH CAHTOA Jan 6 = 1.40 2:50 = 29.25 ZFy=0] ↑ (+) - 20 Cos 29.25-30 cos 29.25 -40 605 29.25 = 0 + Cv + 47.42 (BD Cv = 131·10 KN or 31·10 ²1 ans. знька 20 2 1.45m ΣFh=0] → (+) - Ch + Zo sin 29.25 + 30 sin 29.25+ 40 Sin 29.25 = 0 ch=143.98 kW or 43.98* K Clos
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