College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- A 1.5 kg block is connected by a rope across a 50-cm-diameter, 2.0 kg pulley, as shown. There is no friction in the axle, but there is friction between the rope and the pulley; the rope doesn’t slip. The weight is accelerating upward at 1.2 m/s2. What is the tension in the rope on the right side of the pulley?arrow_forwardA 7-kg mass (m1) hangs from a cord that runs through a pulley and back down to attach to a 6-kg mass (m2) that is hanging from the other side. The pulley has a mass of 5.00-kg and a diameter of 20-cm. Find: A) the tension in the cord supporting m1 and the tension in the cord supporting m2; B) the tension in the cord supporting the pulley. C) Why is the answer to B) not equal to the sum of tensions in A)? Why is it not equal to the sum of the three weights?arrow_forwardSuppose a 905-kg car is on the bridge in the figure with its center of mass halfway between the hinges and the cable attachment. (The bridge is supported by the cable and hinges only.) The mass of the bridge is 2500 kg. Find the tension, in newtons, in the cable.arrow_forward
- A 7-kg mass (m1) hangs from a cord that runs through a pulley and back down to attach to a 6-kg mass (m2) that is hanging from the other side. The pulley has a mass of 5.00-kg and a diameter of 20-cm. Find: A) the tension in the cord supporting m1 and the tension in the cord supporting m2; B) the tension in the cord supporting the pulley. C) Why is the answer to B) not equal to the sum of tensions in A)? Why is it not equal to the sum of the three weights?arrow_forwardA student gets his car stuck in a snow drift. Not at a loss, having studied physics, he attaches one end of a stout rope to the vehide and the other end to the trunk of a nearby tree, allowing for a small amount of slack. The student then exerts a force F on the center of the rope in the direction perpendicular to the car-tree line, as shown in the figure below. If the rope is inextensible and if the magnitude of the applied force is 504 N, what is the force on the car? (Assume equilibrium conditions.) KN 12 m Tree 0.50 marrow_forwardThe figure below shows an arm that is balancing a carton of milk in the hand. The mass of the carton of milk is 1.77 kg, and in the figure is the gravitational force on the carton. The biceps muscle applies a force Fg to the forearm directed up and to the right at an angle of 75.0° from vertical. The point where F is applied to the forearm is 8.00 cm to the left of the elbow joint and 25.0 cm to the right of the center of gravity of the milk carton. (For simplicity, ignore the weight of the forearm.) B Milk N -25.0 cm- What is the magnitude of FB (in N)? 75.0⁰ 8.00 cm iarrow_forward
- It is sometimes important to determine the location of a person’s center of gravity(which coincides with the center of mass because the gravitational force is uniform at the scale of the human body). This can be done with the arrangement shown intheFigure below. A light (negligible mass) plank rests on two scales that read Fg1=380 N and Fg2=320 N. The scales are separated by a distance of 2.00 m. How far from the woman’s feet is her center of gravity?arrow_forwardItem 9 A garage door is mounted on an overhead rail (Figure 1). The wheels at A and B have rusted so that they do not roll, but rather slide along the track. The coefficient of kinetic friction is 0.54. The distance between the wheels is 2.00 m, and each is 0.50 m from the vertical sides of the door. The door is uniform and weighs 900 N. It is pushed to the left at constant speed by a horizontal force F, that is applied as shown in the figure. Figure B k A K 2.00 m -3.00 m h F 1 of 1 If the distance his 1.60 m, what is the vertical component of the force exerted on the wheel A by the track? Express your answer to two significant figures and include the appropriate units. μA ? nA = Value Units Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B If the distance h is 1.60 m, what is the vertical component of the force exerted on the wheel B by the track? Express your answer with the appropriate units. μÅ ? nB = Value Units Submit Request Answer Part…arrow_forward
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