A1 A2 АЗ A4 A5 A6 A1 A2 + A3 + + A4 + A5 А6 What are the possible complementation groups from the data in the table? + + + + + +

The Karyotype • Karyotype [KAER-ee-oh-tihp]: To prepare a karyotype: A cell sample is collected and treated to stop The sample is stained, which produces chromosomes that is clearly visible under a microscope Chromosomes are and The autosomes are numbered, labelled as K » X }( 13 . 19 ❤. 15 20 {{ 10 16 21 on the and the sex chromosomes are 25 12 K= during 22 12 18 Su X/Y

Short Answer 4. You identify two recessive mutations in fruit flies, one that results in curly wings (cc) and one in an ebony body (ee). You cross two flies that are heterozygous for both traits (CcEe), and find 352 flies progeny in the next generation with the following phenotypes: wild type - 193 wild type wings, ebony body - 69 You believe the curly and ebony alleles assort independently and are not linked. Perform a chi square analysis for this cross to test the null hypothesis. A) Show at least the following parts of your work: the expected vs. observed numbers for each phenotype, and the final X² value. Observed Expected (o-e)²/e wild type body, curly wings - 64 curly wings, ebony body - 26 Edit View Insert Format Tools 12pt ✓ Paragraph Table X² U AV T² v BIUA V V QV G✓ ⠀

please help?