a. With 95% confidence the difference in the proportions of Texans and New Yorkers who favor a new Green initiative is between (round to 3 decimal places) and (round to 3 decimal places). b. If many groups of 594 randomly selected Texans and 542 randomly selected New Yorkers were surveyed, then a different confidence interval would be produced from each group. About these confidence intervals will contain the true population proportion of the difference in the proportions of Texans and New Yorkers who favor a new Green initiative and about percent will not contain percent of the true population difference in proportions.

A genetic experiment with peas resulted in one sample of offspring that consisted of 427 green peas and 158 yellow peas. a. Construct a 90% confidence interval to estimate of the percentage of yellow peas. b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations?

CNN is conducting a poll, and wants to produce a 90% confidence interval for the proportion of all New York residents who favor legalizing recreational marijuana. Of the 602 randomly selected New Yorkers surveyed, 394 were in favor of the initiative. a.   With 90% confidence, the proportion of New York residents who favor legalizing recreational marijuana is between  BLANK and BLANK.  b.   Suppose that we survey 602 randomly selected Americans many times, and calculate a confidence interval for each group. About Blank . percent of these confidence intervals will contain the true population proportion of New Yorkers who favor legalizing recreational marijuana, and about BLANK   percent will not contain the true population proportion.

Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)

Suppose that in a recent poll, 550 of the 915 randomly selected U.S. adults agreed with the statement “social media sites like Facebook and Twitter do more to divide the country” (as opposed to unite the country, or neither). a. Use this information to construct a 90% confidence interval.

Suppose the English department of a local university has a  total of 105 faculty members. Of this number, 24 (about 23%) are part-time instructors. Is it appropriate to find a confidence interval for the percentage of part-time instructors in the department? Find a 95% confidence interval  or explain why you should not find a confidence interval for the percentage of part-time instructors in the English department.

15. Pain after surgery: In a random sample of 50 patients undergoing a standard surgical procedure, 15 required medication for postoperative pain. In a random sample of 90 patients undergoing a new procedure, only 16 required pain medication. a. Construct a 95% confidence interval for the difference in the proportions of patients needing pain medication between the old and new procedures. b. A physician claims that the proportion of patients who need pain medication is the same for both procedures. Does the confidence interval contradict this claim? 16

Suppose we wish to estimate the average number of hours per week that Americans watch TV. Use the following data from an SRS to find a 90% confidence interval: 30        64        49        40        21        58        9          43        39            43

According to a poll, 81% of California adults (410 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California.What is a point estimate for the true population proportion?