Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN: 9780134580999
Author: Elaine N. Marieb, Katja N. Hoehn
Publisher: PEARSON
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- Two fruit flies (Drosophila melanogaster) were crossed. The cross was between a homozygous red-eyed, wingless female and a white-eyed male heterozygous for wings. Recall that red eyes (R) is dominant over white eyes (r) and is inherited on the X chromosome (sex-linked) and as such, eye colour alleles should be written as superscript. In addition, the autosomal trait wings (W) is dominant over wingless (w). 1. List the female genotype 2. List the male genotype 3. Construct a Punnett Square for this dihybrid cross on a piece of paper, to determine what the offspring of such a cross would be with respect to sex, eye colour & wings. 4. Using the information from your Punnett Square answer the following: a. What genotypes did you get (list all genotype combinations; if you have more than one of the same kind, you do NOT have to re-list it.) b. What are the phenotypic ratios of the offspring with respect to sex, eye colour and wings?arrow_forwardHere is the URL: https://media.saplinglearning.com/priv/he/bio/punnett-squares/lab.html Thank you!arrow_forwardI * 1 1 I 2 1 13 1 14 1 16r 1 11171 Using the pedigree you have constructed, complete the following Punnett square using A/a. 1) Show the cross between Baila and her non-albino husband if he had no Mother's Alleles albinism in his family history: Mother's genotype: Father's genotype: Genotype %: Phenotype %: o add speaker notes Father's Allelesarrow_forward
- What phenotypes in what ratio would be expected in the F2 generation of the cross with the following information: The genotype of homozygous black, long haired rabbit is BBhh The genotype of homozygous brown, short haired rabbit is bbHH The gamete of homozygous black, long haired rabbit is Bh The gamete of homozygous brown, short haired rabbit is bH F1 progeny is BbHh (heterozygous black, short haired rabbit)arrow_forwardIn this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected || IV V 5600 orize 077808 15 10 9 10 CHO વ Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual does not display the disease phenotype. Carriers of the disease are not indicated. Information on disease status is not known for generation I and is omitted for the individuals represented by a symbol with an asterisk.…arrow_forwardThe pedigree below shows a family with a history of an autosomal recessive genetic disease with one individual's genotype indicated (G denotes the normal allele and g denotes the disease-causing allele). * O 0 O 1/8 1/4 O 1/16 Individual 1's father is known to be heterozygous (*) and his mother is known to be homozygous dominant. Other individuals in the pedigree may be carriers, but are not marked. The question mark (?) indicates that you do not yet know anything about this individual's phenotype with regard to the disease. Part 1 What is the probability that individuals 1 and 2 will have a child (5) who is a male with the disease (the child is unborn and the sex is not yet known)? O 1/4 1 O 1/6 5 1/8 2 01/12 gg 3 Part 2 What is the probability that the daughter (female)(6) that individual 3 and 4 just had will have the disease? 6arrow_forward
- In the following cross, imagine that you have a female fly that has two Xs and one Y due to a nondisjunction event in her mother's germ cells. Draw out what the possible gametes are for both the female and the male and also a Punnett square showing the genotypes, phenotypes, and sex of the possible flies as a result of this cross. You do not need to provide the probabilities of each of these. Red-eyed wi C Ở Red-eyed wt XX Y X Y Meiosisarrow_forwardPlease consider the pedigree below. There are no cases of false paternity. AB 2 I II 2 3 A (AB A)B 1 III 2 3 4 IV B 1 2 a. Which individual/s definitely has/have Bombay phenotype in this extended family? b. What are the genotypes of individuals II-2 and II-3 at the ABO and H loci?arrow_forwardFrank and Susan both have freckles but they're firstborn son Lawrence does not demonstrate the characteristics. What are the most likely genotype of Frank Susan and Lawrence?arrow_forward
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