A. Let g(t) be the solution of the initial value problem with g(1) = 1. Find g(t). g(t) = B. Let f(t) be the solution of the initial value problem with f(0) = 0. Find f(t). f(t) C. Find a constant c so that = solves the differential equation in part B and k(1) = 6. C = dy dt 3t- 3t +y=0, t > 0, dy dt +y=t² k(t) = f(t) + cg(t)
A. Let g(t) be the solution of the initial value problem with g(1) = 1. Find g(t). g(t) = B. Let f(t) be the solution of the initial value problem with f(0) = 0. Find f(t). f(t) C. Find a constant c so that = solves the differential equation in part B and k(1) = 6. C = dy dt 3t- 3t +y=0, t > 0, dy dt +y=t² k(t) = f(t) + cg(t)
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 10CR
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Transcribed Image Text:A. Let g(t) be the solution of the initial value problem
with g(1) = 1.
Find g(t).
g(t) =
B. Let f(t) be the solution of the initial value problem
with f(0) = 0.
Find f(t).
f(t)
C. Find a constant c so that
=
solves the differential equation in part B and k(1) = 6.
C =
3t
dy
dt
3t
+y = 0, t > 0,
dy
dt
+y=t²
k(t) = f(t) + cg(t)
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