solve the one dimensional wave equation with the boundary conditions and inital conditions as given below: δ2u/δt2 = 1/pi2.δ2u/δx2 u(0,t)= 0, t>0. u(1,t)=0, t>0 u(x,0)= sinππxcosπx, 0

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A: Solution: As per our guideline we are supposed to answer only first three question please repost…

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A: Step 1: Step 2: Step 3: Step 4:

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A: Hello, thanks for your question but according to our policy I am answering the first three subparts.…

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A: dy/dx and d2y/dx2  are find in next step dy/dx = (dy/dt) /(dx/dt)

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A: Given y2=x2+2xy

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A: The given function y=3x2-5x. We have to find the value of dydt at x=2 and dxdt=2.

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A: See the attachment

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A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

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