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- The purpose of this assignment is to understand the role of margin of error in constructing confidence interval when population standard deviation (δ) is known and unknown. Develop 90 %, 95 %, and 99% confidence intervals for population mean (µ) when sample mean is 10 with the sample size of 100. Population standard deviation is known to be 5. Suppose that sample size changes to 144 and 225. Develop three confidence intervals again. What happens to the margin of error when sample size increases? A simple random sample of 400 individuals provides 100 yes responses. Compute the 90%, 95%, and 99% confidence interval for population proportion (p). With the same random sample as in 3, if the sample size increases to 1000, what happens to the three confidence intervals?Which of the following would result in the narrowest confidence interval? OA sample size of 30 with 95% confidence. OA sample size of 100 with 95% confidence OA sample size of 30 with 99% confidence. OA sample size of 100 with 99% confidence.Calculate the lower confidence limit (LCL) and upper confidence limit (UCL) of the mean for each of the following. a. x = 335, n = 241, o=50, and x = 0.05 b. x = 365, n = 418, o² = 81, and a = 0.01 a. LCL = UCL = b. LCL = UCL = (Round to two decimal places as needed.) (Round to two decimal places as needed.) (Round to two decimal places as needed.) (Round to two decimal places as needed.)
- If n=29, x¯=48, and s=13, construct a confidence interval at a 90% confidence level. Assume the data came from a normally distributed population.( , )Give your answers to one decimal place.7. (Sec. 7.2) In a survey of 2004 American adults, 501 of them said that they believed in astrology (a) Calculate and interpret a confidence interval at the 95% confidence level for the proportion of all adult American adults who believe in astrology (b) Calculate and interpret a 95% lower confidence bound for the proportion of all adult American adults who believe in astrologyFind t and p value and construct a confidence interval
- Free of CVD Prevalent CVD Total Men 1548 244 1792 Women 1872 135 2007 Total 3420 379 3799 A. Generate a 95% confidence interval for the true proportion of women with CVD. B. Generate a 95% confidence interval for the true proportion of men with CVD.tion. Use this information to construct the 90% and 95% confidence intervals fc of the confidence intervals. ce of a certain stock was $123.13. Assume the population standard deviation isIf n = 280 and p (p-hat) = 0.8, construct a 90% confidence interval. Give your answers to three decimals