Free of CVD       Prevalent CVD    Total Men          1548                 244                 1792 Women    1872                  135                 2007 Total          3420                 379               3799   A. Generate a 95% confidence interval for the true proportion of women with CVD. B. Generate a 95% confidence interval for the true proportion of men with CVD.

If n= 220, p-hat= .4, then what will be the 87.4% confidence interval for the population proportion?

A sample of 1100 observations taken from a population produced a sample proportion of 0.36 . Make a 90 % confidence interval for p . Round your answers to three decimal places.

Imagine that a researcher appropriately conducts a z test and then calculates a correseponding 95% confidence interval. When calculating that 95% confidence interval, the researcher should center the confidence interval on... a. the population mean b. the sample mean c. the population standard deviation

If a school district takes a random sample of 50 Math SAT scores and finds that the average is 471, and knowing that the population standard deviation of Math SAT scores is intended to be 100. Find a 99% confidence interval for the mean math SAT score fo this district.

magine that you conduct a study and estimate that the prevalence of hypertension among employees of a company. Your estimated prevalence is 24%. You also calculate a margin of error for a 95% confidence interval associated with this prevalence estimate of 3%.  What would be the 95% confidence interval for the prevalence calculated from this study?

Which one of the following statements about confidence intervals is false?   Given the same sample of data, a 99% confidence interval will be wider than a 95% confidence interval. The size of the population affects the width of a confidence interval. The sample statistic determines the center of the confidence interval. The value of z* affects the width of a confidence interval. The general format of a confidence interval is “sample statistic ± margin of error.”

If n=19, ¯xx¯(x-bar)=42, and s=7, construct a confidence interval at a 95% confidence level. Assume the data came from a normally distributed population.Give your answers to one decimal place.

If n=13, ¯xx¯(x-bar)=37, and s=9, construct a confidence interval at a 80% confidence level. Assume the data came from a normally distributed population. Give your answers to one decimal place.

now find the 99% confidence interval given the same information, x=13