a. Explain what it would mean to make a type I error. Choose the correct answer below. A. A type I error would occur if in fact μ>0.56​ppm, but the results of the sampling lead to the conclusion that μ=0.56 ppm.   B.A type I error would occur if in fact μ>0.56 ​ppm, but the results of the sampling fail to lead to the conclusion that μ=0.56 ppm. C.A type I error would occur if in fact μ=0.56 ​ppm, but the results of the sampling lead to the conclusion that μ>0.56 ppm. D. A type I error would occur if in fact μ=0.56​ppm, but the results of the sampling fail to lead to the conclusion that μ>0.56 ppm. Part 2 b. Explain what it would mean to make a type II error. Choose the correct answer below. A. A type II error would occur if in fact μ>0.56​ppm, but the results of the sampling fail to lead to the conclusion that μ>0.56 ppm. B. A type II error would occur if in fact μ>0.56 ​ppm, but the results of the sampling lead to the conclusion that μ>0.56 ppm. C. A type II error would occur if in fact μ=0.56 ppm​, but the results of the sampling lead to the conclusion that μ>0.56 ppm. D. A type II error would occur if in fact μ=0.56 ppm​, but the results of the sampling fail to lead to the conclusion that μ>0.56 ppm. Part 3 c. Explain what it would mean to make a correct decision. Choose the correct answer below. A. A correct decision would occur if μ=0.56ppm and the results of the sampling lead to the rejection of that​ fact; or if μ>0.56 ppm and the results of the sampling do not lead to that conclusion. B. A correct decision would occur if μ≠0.56ppm and the results of the sampling lead to the rejection of that​ fact; or if μ=0.56 ppm and the results of the sampling do not lead to that conclusion.   C. A correct decision would occur if μ>0.56 ppm and the results of the sampling do not lead to the rejection of that​ fact; or if μ≠0.56 ppm and the results of the sampling lead to that conclusion. D. A correct decision would occur if μ=0.56ppm and the results of the sampling do not lead to the rejection of that​ fact; or if μ>0.56 ppm and the results of the sampling lead to that conclusion. Part 4

Two independent random samples resulted in the following. Find the estimate for the standard error for the difference between two means. (Give your answer correct to two decimal places.) Sample A: na = 30, sa= 8.4 Sample B: nb = 23, sb = 11

Biologists studying horseshoe crabs want to estimate the percent of crabs in a certain area that are longer than 35 centimeters. The biologists will select a random sample of crabs to measure. Which of the following is the most appropriate method to use for such an estimate? Select either A, B, C, D, E   A one-sample Z-interval for a population proportion A A one-sample Z-interval for a sample proportion B A two-sample Z-interval for a population proportion C A two-sample Z-interval for a difference between population proportions D A two-sample Z-interval for a difference between sample proportions E

If a sample of n = 4 scores is obtained from a normal population with µ = 70 and σ = 12, what is the z-score corresponding to a sample mean of M = 69?     a. z = +1.25   b. z = -1.25   c. z = -0.17   d. z = +0.17

Which of the following samples will have the smallest value for the estimated standard error? A   n = 23 with s2 = 77 B   n = 23 with s2 = 185 C   n = 88 with s2 = 77 D   n = 88 with s2 = 185

7.1.36-T 34.31%, 5.83 of 17 pts A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimate the percentage of computers that use a new operating system. How many computers must be surveyed in order to be 99% confident that his estimate is in error by no more than four percentage points? Complete parts (a) through (c) below. Question Help ▼ a) Assume that nothing is known about the percentage of computers with new operating systems. (Round up to the nearest integer.) Enter your answer in the answer box and then click Check Answer. 2 parts remaining Clear All Check Answer F9 F10 F8 吕0 F3 F6 F7 F4 F5 esc F2 F1 & %24 4 @ de 6. 7 8. 6. 5 E R T Y G H. K F #3

You obtain a sample chi-square value of x2= -5.49. On the basis of this value, you know that   a. there is a negative association between your two variables. b. the observed frequencies are higher than the expected frequencies across at least half of your cells. c. you have made a calculation error; chi-square values cannot be negative. d. the observed frequencies are lower than the expected frequencies across all cells.

Suppose the standard deviation of the sample mean is equal to 0.6. If a sample of size n=100n=100 is collected, what is the population standard deviation?

Suppose a variable x has population mean μ - 39.45 and standard deviation o = = 2.67. Determine the standard error (SE) of the sampling distribution of the mean of a simple random sample of size n = 12. Give your answer precise to two decimal places. Answer: Check

A sample of 12 measurements has a mean of 24 and a standard deviation of 3.75. Suppose that the sample is enlarged to 14 measurements, by including two additional measurements having a common value of 24 each. A. Find the mean of the sample of 14 measurements. Mean = B. Find the standard deviation of the sample of 14 measurements. Standard Deviation =