a. Draw a voltaic cell that could be used to study the reaction shown below.  Mg(s) + 2Ag+(aq) ---> Mg2+(aq)+2Ag(s) b. Write a cell notation to represent the voltaic cell you have drawn above.

Enter electrons as e. Use smallest possible integer coefficients for ALL reactions. If a box is not needed, leave it blank. A voltaic electrochemical cell is constructed in which the anode is a Mg2+ Mg half cell and the cathode is a Hg2+ | Hg half cell. The half-cell compartments are connected by a salt bridge. Write the anode reaction. Write the cathode reaction. + Write the net cell reaction. In the external circuit, electrons migrate Mg2+ Mg electrode. In the salt bridge, anions migrate Mg compartment. + + + the Hg2+ Hg electrode the Hg2+ Hg compartment the the Mg2+|

Set up a cell that has a Mg electrode in a 1.0 M aqueous Mg²+ solution on the left side and a Cu electrode in a 1.0 M aqueous Cu2+ solution on the right side. Add the salt bridge. What is the anode of this system? the Cu electrode the Mg electrode What is the cathode of this system? the Cu electrode O the Mg electrode

True or false, The electrode in a half-cell is always part of the half-reaction?

4. Name EXPERIMENT 12 ELECTROCHEMISTRY: GALVANIC CELLS Electrodes Use the table of standard reduction potentials from your textbook to complete the following table. The zinc-copper Daniell cell is given as an example. Cu Cu Zn Zn Zn Cu Zn Mg Cu Mg Conc. of Each Cation 1.0 M Zn²+ 0.5 M Cu²+ 1.0 M Zn²+ 0.1 M Cu²+ Date 1.0 M Zn²+ Zn²+ + 2e-Zn (ag) Half-Reactions A. Determine the E for the Standard Zn-Cu Galvanic Cell Zn²+ (aq) 1.0 M Cu²+ Cu²+ +2e-Cu Cathode B. Determine the E* for the Cu-Zn Cell at Non-standard Concentrations 1.0 M Zn²+ Anode + 2e → Zn Instructor Cu²+2e-Cu Zn²+ + 2e → Zn (aq) Report Sheet Cathode or Anode? Anode E E (table) (calcd) -0.76 V +0.34 V -0.76V Cathode 0.34 v anode 0.76v Cathode 0.34 v Cu²+ + 2e - Cul C. Determine the E for Zn-Mg and Cu-Mg Galvanic Cells Zn(aq) +2e Zn (s) cathode -0.76 1.0 M Mg²+Mga+2e Mg(s) anode -2.38 +1.10 V 1.10 V 1.0 M Cu²+ +Ze Cu(s) Cathode 40.34 v 2+ +2e 1.0 M Mg²+ M Mg(s) anode -2.38v "You must use the Nernst equation to calculate this…