A. Directions: Give the expected genotypes and phenotypes of the following crosses. Use the Punnett square. a. Two heterozygous purple peas; b. Heterozygous tall and short pea; c. Homozygous round and wrinkled
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The question below, indicate also the genotype and
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- A. Consider this cross before answering the following questions:A pea plant heterozygous for the first trait and recessive for the second trait is crossed with a pea plant heterozygous for the first trait and homozygous-dominant for the second trait. 1. If the first gene is demonstrating dominant epistasis to the second gene, what is the probability that the F1 progeny will expressa. the dominant feature for the second trait?b. the recessive feature for the second trait?c. Neither dominant nor recessive features for the second trait?ibri 12 BIU A - A 4. 11. Mendel crossed peas having round seeds and yellow cotyledons with peas having wrinkled seeds and green cotyledons. All the F1 plants had round seeds with yellow cotyledons. a. What are the genotypes of the parent plants? b. What gametes could be produced by the parent with round seeds and yellow cotyledons? C. What gametes could be produced by the parent with wrinkled seeds and green cotyledons? d. What is the genotype of the F1 plants? e. What gametes could be produced by the F1 plants? hpa. State a hypothesis explaining the inheritance of flower color in painted tongues. b. Assign genotypes to the parents, F₁ progeny, and F2 progeny for all five crosses. c. In a cross between true-breeding yellow and true-breeding lavender plants, all of the F1 progeny are bronze. If you used F₁ plants to produce and F2 generation, what phenotypes in what ratios would you expect? Are there any genotypes that might produce a phenotype that you cannot predict from earlier experiments, and if so, how might this alter the phenotypic ratios among the F2 progeny?
- a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…A. Consider this cross before answering the following questions:A pea plant heterozygous for the first trait and recessive for the second trait is crossed with a pea plant heterozygous for the first trait and homozygous-dominant for the second trait. 1. It there is incomplete dominance in the expression of the two traits, what is the probability that the F1 progeny will be a. expressing the dominant feature for the second trait?b. expressing the dominant feature for both traits?c. expressing the dominant feature for the first trait and recessive feature for the second?d. expressing recessive feature for the first trait?e. expressing recessive feature for both traits?a. A variety of fruit bearing plants with the dominant allele A produces cream-coloured fruit while aa plants produce pink or red fruit. Red fruit is produced if allele B is present, and pink fruit is produced when the genotype is bb. What are the expected F2 phenotypes and proportions from intercrossing the F1 offspring of a cross between two plants with the genotype AAbb and aaBB? b. A certain animal can have brown, red, black or gray fur. Assume that fur colour is controlled by a single gene with multiple alleles in a dominance series where black (B1) > brown (B2) > red (B3) > gray (B4). Give the genotypes of two phenotypically different heterozygotes that when crossed produce offspring with the phenotypic ratio of 1 red : 2 black : 1 brown.
- I. Assume that there is no interference in the Lf-W region. The cross between the triple heterozygote (Lf J W/ lf j w) and a triple homozygous recessive produced 375 progenies. Give the frequency of each specific progeny type: a. with crossover in the Lf-J and J-W regions b. with crossover in the Lf-J region c. with crossover in the J-W region d. without crossover in the Lf-W region II. Assume that there is complete interference in the Lf-W region. The cross between the triple heterozygote (Lf J W/ lf j w) and a triple homozygous recessive produced 350 progenies. Give the frequency of each specific progeny type: a. with crossover in the Lf-J and J-W regions b. with crossover in the Lf-J region c. with crossover in the J-W region d. without crossover in the Lf-W regiona. In a type of plant, pink flowers (P) is dominant over white flowers (p), and tall (T) is dominant over short (t). Determine the genotypes of the parents in the following cross: Pink, tall x pink, short O / pink, tall: /s pink, short: /s white, tall: / white, short Genotypes: () (ii) Phenotypes: Pink, tall Pink, short b. A woman has blood type A MM. She has a child with blood type O MN. Which of the following men could not be the child's father? Explain your reasoning. Man Blood type Peter O NN Rob AB MN Doug B MN Simon A NN Mike АВ МIntroduction: A dihybrid cross is a cross between individuals that involves two pairs of contrasting traits. To Predict the results of a dihybrid, cross all possible combinations of the four alleles from each parent must be considered. You will examine a dihybrid cross involving both color and texture. Purple (P), is dominate to yellow (p), and smooth texture (S) is dominant to wrinkled (s). Both parent plants are heterozygous for both traits. Review genetics and the use of Punnett squares in a biology text before doing this experiment.MATERIALS: Assume you have ear of Corn. You need a heterozygous X heterozygous 9:3:3:1, purple/yellow, starchy/sweet. PROCEDURE: From above please write out: The crop The parental (P) cross phenotype, genotype, gametes Cross between two F1 Selfed testcross 1. First let us use a Punnett square to examine the theoretical outcome of the Heterozygous X Heterozygous dihybrid cross. USE a Punnett square. REMEMBER: a phenotype is how the offspring will…
- A. Theoretical: The Punnett square will be used to examine the theoretical outcome of possible monohybrid crosses. 1. The first cross is between a Homozygous dominant parent (PP), and a Homozygous recessive or just simply say recessive parent (pp): a. Fill in the Punnett square. Each box represents a genotype possibility for an offspring. b. Place the allele donated by each parent in the corresponding box. Now list the possible genotypes and their corresponding phenotype. c. If an individual's genotype is heterozygous, the dominant trait will be expressed in the phenotype. Give the percent possible for the phenotypes. P Genotype: p Phenotype: Phenotype % probable: 1| Page 2. Cross between a Homozygous dominant parent (PP) and a Heterozygous parent (Pp). Fill in as in step one. 3. Cross between a Heterozygous parent (Pp), and another Heterozygous parent (Pp). Fill-in as before. 4. Test cross: A test cross is between a recessive parent (pp), and a Heterozygous parent (Pp). Again, fill-in…a. What type of trait is this? How many genes and alleles are involved? Explain your answer. b. What are the genotypes of the 90 and 100 cm plants respectively in the parental generation? c. What is the possible genotype, or genotypes, of the 95 cm class in the F2? c. What is the possible genotype, or genotypes, of the 95 cm class in the F2?Consider the following cross examining four gene in two parental line: Parent 1: A/a; B/B; D/d; E/e Parent 2: A/a; B/b; d/d; e/e Assuming independent assortment for the four genes, what fraction of progeny will be phenotypically identical to either parent 1 or parent 2? (Hint: first figure out the fraction of progeny that resembles parent 1 and parent 2 separately, then get the overall fraction.) 9/16 1/16 3/4 3/8 3/16