a. [CH3 COOH] = 0.85 M, [CH;CO0-] = 0.45 M (the pK, for acetic acid is 4.74) pH = b. [Н,РО, ] 3 0.50 М, НРО,2| — 0.20 M (the pK, for H,РO, is 7.21) pH = c. [HSO3] = 1.85 M, SO3² = 0.60 M (the pK, for HS03¯ is 7.00) pH =
a. [CH3 COOH] = 0.85 M, [CH;CO0-] = 0.45 M (the pK, for acetic acid is 4.74) pH = b. [Н,РО, ] 3 0.50 М, НРО,2| — 0.20 M (the pK, for H,РO, is 7.21) pH = c. [HSO3] = 1.85 M, SO3² = 0.60 M (the pK, for HS03¯ is 7.00) pH =
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter15: Acid–base Equilibria
Section: Chapter Questions
Problem 95AP
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![[References]
Calculate the pH of buffers that contain the acid and conjugate base concentrations listed below.
a. [CH3 COOH] = 0.85 M, [CH3 COO¯] = 0.45 M (the pK, for acetic acid is 4.74)
pH =
b. [H2PO4-] = 0.50 M, HPO,? = 0.20 M (the pK, for H2PO4 is 7.21)
%3D
pH =
c. [HSO;¯] = 1.85 M, SO32|
= 0.60 M (the pK, for HSO; is 7.00)
с.
pH =
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Transcribed Image Text:[References]
Calculate the pH of buffers that contain the acid and conjugate base concentrations listed below.
a. [CH3 COOH] = 0.85 M, [CH3 COO¯] = 0.45 M (the pK, for acetic acid is 4.74)
pH =
b. [H2PO4-] = 0.50 M, HPO,? = 0.20 M (the pK, for H2PO4 is 7.21)
%3D
pH =
c. [HSO;¯] = 1.85 M, SO32|
= 0.60 M (the pK, for HSO; is 7.00)
с.
pH =
Submit Answer
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