a. b. Br Br CH3OH CH3O OCH 3 OCH 3 OCH3 б

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Which of these is the correct rotation for [a] of 0°?
### Transcription for Educational Website

The image presents two chemical reactions illustrating the substitution of a bromine atom in an organic compound with a methoxy group (OCH₃).

#### Reaction a:
- **Starting Material:** 
  - A chiral alkyl bromide with the bromine (Br) atom connected to a carbon, shown with a wedge to indicate its spatial orientation.
- **Reagent:** 
  - Methanol (CH₃OH).
- **Products:** 
  - Two isomers, where the bromine is substituted by an OCH₃ group.
  - Both the methoxy groups (OCH₃) are shown with different spatial orientations:
    - One with a wedge indicating that the OCH₃ group is in the same orientation as the original Br.
    - The other with a dashed line showing inversion of configuration compared to the original Br.

#### Reaction b:
- **Starting Material:** 
  - Similar chiral alkyl bromide starting material as in Reaction a.
- **Reagent:** 
  - Methoxide ion (CH₃O⁻).
- **Products:** 
  - Similar to Reaction a, it produces two isomers with the methoxy group substituting the bromine, depicted with different configurations of the OCH₃ group:
    - One with a wedge (same spatial orientation as original Br).
    - Another with a dashed line (inverted orientation compared to original Br).

### Explanation 
- Both reactions demonstrate nucleophilic substitution where the bromine is replaced by an -OCH₃ group.
- The use of different reagents (CH₃OH vs. CH₃O⁻) can lead to changes in reaction conditions and possibly reaction mechanisms (like SN1 or SN2).
- The difference in the spatial orientation of the product isomers indicates stereochemistry considerations in such reactions.
Transcribed Image Text:### Transcription for Educational Website The image presents two chemical reactions illustrating the substitution of a bromine atom in an organic compound with a methoxy group (OCH₃). #### Reaction a: - **Starting Material:** - A chiral alkyl bromide with the bromine (Br) atom connected to a carbon, shown with a wedge to indicate its spatial orientation. - **Reagent:** - Methanol (CH₃OH). - **Products:** - Two isomers, where the bromine is substituted by an OCH₃ group. - Both the methoxy groups (OCH₃) are shown with different spatial orientations: - One with a wedge indicating that the OCH₃ group is in the same orientation as the original Br. - The other with a dashed line showing inversion of configuration compared to the original Br. #### Reaction b: - **Starting Material:** - Similar chiral alkyl bromide starting material as in Reaction a. - **Reagent:** - Methoxide ion (CH₃O⁻). - **Products:** - Similar to Reaction a, it produces two isomers with the methoxy group substituting the bromine, depicted with different configurations of the OCH₃ group: - One with a wedge (same spatial orientation as original Br). - Another with a dashed line (inverted orientation compared to original Br). ### Explanation - Both reactions demonstrate nucleophilic substitution where the bromine is replaced by an -OCH₃ group. - The use of different reagents (CH₃OH vs. CH₃O⁻) can lead to changes in reaction conditions and possibly reaction mechanisms (like SN1 or SN2). - The difference in the spatial orientation of the product isomers indicates stereochemistry considerations in such reactions.
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