a. An eccentric load of 95 kN acts on a bracket as shown in Figure 6 at its free end. In the configuration shown in Figure 6, the seven (7) rivets are of the same diameter and the allowable shear stress is 10000 N/cm?. Neglecting the weight of the bracket determine the minimum rivet diameter required to avoid failure. 95kN

a. An eccentric load of 95 kN acts on a bracket as shown in Figure 6 at its free end. In the configuration shown in Figure 6, the seven (7) rivets are of the same diameter and the allowable shear stress is 10000 N/cm?. Neglecting the weight of the bracket determine the minimum rivet diameter required to avoid failure. 95kN

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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We will use both shearing and bearing analysis to determine the quantities of rivets needed to fasten BC and BE. We can determine two values then choose what will be more safe. ■ For Member BC: ■ Based on Shearing: V T == ■ Av Based on Bearing: P Ab 70MPa = 96000 N .n. (19) ²x n 1/4. π n = 4.84 5 rivets 96000 N (19mm) (6mm) xn 140MPa n = 46.015≈ 7 rivets For member BC, we must use 7 rivets since we must need a minimum of 7 rivets to resist bearing stress produced by the connection. If we only use 5 rivets, then the bearing stress will become 168.42 MPa. It will result to failure since the allowable bearing stress is only 140 Mpa. ■ For member BE: (Practice at Home) Pac EXAMPLE: 5. The figure shows a roof truss and the detail of the riveted connection at joint B. Using allowable stresses of t = 70 MPa and ob= 140 MPa, how many 19-mm diameter rivets are required to fasten member BC to the gusset plate? Member BE? What is the largest average tensile or compressive stress in BC and BE? Say…
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