1cmt1 (cm)P3,2 cm t2 (cm)t1 (cm) 1 cm20 cm Ь (ст)P = 20t%3DDp=1,6 cm * Find the Maximum shear, clush and tear (tensile)stresses in the rivets and plates in the annex.+ Rivet diameter is Dp (cm)* Is the jointsafe6hroct:an, rafety = 2800 kg/em?in case of앙Ctraction, safety = 2.800 kg/cm2safety=1600kglam2tersile, safety= lu0okg/cm2Inuestigate!00

Answered: Image /qna-images/answer/e7b8ac8f-50f5-4d41-924c-0864b52eb848.jpg

Answered: 1cm t1 (cm) →P 3,2 cm t2 (cm) t1 (cm) 1…

Engineering

Mechanical Engineering

1cm t1 (cm) →P 3,2 cm t2 (cm) t1 (cm) 1 cm 中中 20 çm b (cm) P. →P P = 20t Dp=1,6 cm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Q 18 please
3. A 5.0 inches cube chiffon cake on a table was exposed to a shearing force of 0.20 lb. The upper surface was displaced by 0.80 inches. What is the Shear Modulus of the cake ( lb/in ^2)
A) 2*F(AC) i - 3*F(AC) j D B) F(AC)j 3 m y A 2 m C) F(AC) k 4 m B AB F(AB)=Dtension force in AB D) F(AC) i F= F(AD)=tension force in AD AD F = F(AC)=tension force in AC AC Weight of the flowerpot is 40 Newton. E) 4*F(AC)j +3* F(AC) k W=weight of the flowerpot Express the tension force in AC as a vector form.
4 I. a docs.google.com/forms/d/e/1FAlpQLSet : Untitled Section F1- 10 kN F2 = 26 kN - 45 F3 =8 kN BI 4 m F4= 44 kN Va -45 F5 = 8 kN 1] What is the resultant moment of the five forces acting on the rod about point A? a) 77.5 kN.m b) 108.1 kN.m e) 59.8 kN.m d) 153.1 kN.m e) 23.1 kN.m n 86.4 kN.m 2] What is the resultant moment of the five forces acting on the rod about point C? a) 44.5 kN.m b) 187.1 kN.m c) 59.8 kN.m d) 153.4 kN.m e) 99.1 kN.m ) 86.4 kN.m 3] What is the moment of the force F1 about point E? a)- 14.6 kN.m b)- 106.1 kN.m )-45.8 KN.m d) - 215.8 KN.m e) - 99.7 kN.m 0- 188.1 kN.m 4] What is the moment of the force F2 about point D? a) 19.5 kN.m b) 122.1 kN.m c) 88.8 kN.m d) 147.1 kN.m e) 58.1 kN.m ) 135.4 kN.m 5] What is the moment of the force F5 about point A? a) 11.8 kN.m b) 5.7 kN.m e) 44.S kN.m d) 19.1 kN.m e) 69.4 kN.m )1.4 kN.m * ;The answer is [1 a O ->
Solve it correctly please. I will rate accordingly. SOLVE a,b,c
explain me the whole process do integration for each step properly
Q1 // Choose the correct answer: 1- A fluid is one which can be defined as a substance a) Has some shear stress at all points. b) Can deform indefinitely under the action of the smallest shear force. c) Has the small shear stress in all directions 2- What is mean by an incompressible fluid? a) Density change with pressure. b) Density does not change with pressure. c) Neither a. or b. 3- A piemeter is used to measure positive gauge pressure of liquid and only limited to low pressure measurement a) b) c) True. False. Neither a or b. 4- The correct water pressure (ywater 9810 N/m') at a depth of 10 m in a tank is open to atmosphere is 98100 K pa gage 98100 pa gage 9.81 pa gage a) b) 5- Which is the expensive device for measuring flow/discharge rate Venturi meter a) b) c) Pitot tube Orifice meter
719 @ • ৭:৭, 3G ZAIN IQ li. خاص A docs.google.com Untitled Section F1 = 5 kN F2 = 13 kN )- 60° F3 = 4 kN 6-45 4 m 8 m F4 = 22 kN D El Ja = 30° F5 = 4 kN 1] What is the resultant moment of the five forces acting on the rod about point A? a) 3.5 kN.m b) 16.2 kN.m c) 20.2 kN.m d) 11.5 kN.m e) 33.1 kN.m f) S.1 kN.m 21 What is the resultant moment of the five forces acting on the rod about point C? a) 47.5 kN.m b) 55.5 kN.m c) 12.2 kN.m d) 61.9 kN.m e) 79.1 kN.m ) 44.1 kN.m 3] What is the moment of the force F1 about point E? а)- 22.8 kN.m b) - 49.5 kN.m c) - 55.9 kN.m d) - 9.1 kN.m e) - 12.7 kN.m f) - 25.9 kN.m 4] What is the moment of the force F2 about point D? a) 40.5 kN.m b) 71.5 kN.m c) 14.2 kN.m d) 64.5 kN.m e) 56.1 kN,m ) 39.1 kN.m 5] What is the moment of the force F5 about point A? a) – 17.8 kN.m b) - 4.8 kN.m c) - 12.9 kN.m d) - 8.1 kN.m e) - 32.7 kN.m f) - 2.9 kN.m ;The answer is [1 * a
The moment of inertia of the profile below in relation to Y is valid. Make the calculation memo of the question:
Q 4 please
у - ахis Fs F4 F1 X - axis F3 F2 Figure (2)
please solve question 15 thaaanks sir