A Y-connected balanced three-phase generator with an impedance of 0.4 + j0.3 N per phase is connected to a Y-connected balanced load with an impedance of 24 + j19 N per phase. The line joining the gen- erator and the load has an impedance of 0.6 + j0.7 N per phase. Assuming a positive sequence for the source voltages and that Van 120/30° V, find: (a) the line voltages, (b) the line currents.
A Y-connected balanced three-phase generator with an impedance of 0.4 + j0.3 N per phase is connected to a Y-connected balanced load with an impedance of 24 + j19 N per phase. The line joining the gen- erator and the load has an impedance of 0.6 + j0.7 N per phase. Assuming a positive sequence for the source voltages and that Van 120/30° V, find: (a) the line voltages, (b) the line currents.
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.19P: Consider a single-phase load with an applied voltage v(t)=150cos(t+10)volts and load current...
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![A Y-connected balanced three-phase generator with an impedance of
0.4 + j0.3 N per phase is connected to a Y-connected balanced load
with an impedance of 24 + j19 n per phase. The line joining the gen-
erator and the load has an impedance of 0.6 + j0.7 N per phase.
Assuming a positive sequence for the source voltages and that Van =
120/30° V, find: (a) the line voltages, (b) the line currents.
Answer: (a) 207.8/60° V, 207.8/-60° V, 207.8/-180° V,
(b) 3.75/-8.66° A, 3.75/-128.66° A, 3.75/111.34° A.
AR](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9a2d53f8-d51c-41b8-99f5-1be6774bd3fb%2Fe9502593-d8aa-4023-bc58-a9e880c834a9%2F4gtwed_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A Y-connected balanced three-phase generator with an impedance of
0.4 + j0.3 N per phase is connected to a Y-connected balanced load
with an impedance of 24 + j19 n per phase. The line joining the gen-
erator and the load has an impedance of 0.6 + j0.7 N per phase.
Assuming a positive sequence for the source voltages and that Van =
120/30° V, find: (a) the line voltages, (b) the line currents.
Answer: (a) 207.8/60° V, 207.8/-60° V, 207.8/-180° V,
(b) 3.75/-8.66° A, 3.75/-128.66° A, 3.75/111.34° A.
AR
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