A wire with a current of 6.4 A is in a uniform magnetic fieldB - Bai + By] + B,kWhere B= =8.9T. and By =45T, and Be =44.8T are the components of the magnetic field.The wire is oriented along the x-axis and is carrying the current in the +x direction and has a length 7.76mWhat is the magnitude of the magnetic force on the wire (in INy?I need to show all work A wire with a current of 6.4A is in a uniform magnetic fieldB = B₂i+By+ B₂kWhere B 8.9T, and By =-45T, and B₂ =44.8T are the components of themagnetic field.The wire is oriented along the x-axis and is carrying the current in the +x directionand has a length 7.76mWhat is the magnitude of the magnetic force on the wire (in N)?I

Current is The magnetic field vector is Components of magnetic field vector are , and Length of…

Answered: A wire with a current of 6.4A is in a…

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter24: Magnetic Fields

Section: Chapter Questions

Problem 67A

See similar textbooks

Related questions

Concept explainers

Question

A wire with a current of 6.4 A is in a uniform magnetic field B - Bai + By] + B,k Where B= =8.9T. and By =45T, and Be =44.8T are the components of the magnetic field. The wire is oriented along the x-axis and is carrying the current in the +x direction and has a length 7.76m What is the magnitude of the magnetic force on the wire (in INy? I need to show all work

A wire with a current of 6.4A is in a uniform magnetic field
B = B₂i+By+ B₂k
Where B 8.9T, and By =-45T, and B₂ =44.8T are the components of the
magnetic field.
The wire is oriented along the x-axis and is carrying the current in the +x direction
and has a length 7.76m
What is the magnitude of the magnetic force on the wire (in N)?
I

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 19 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions