College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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![**Problem Statement:**
A 37 N block rests on an inclined plane with a slope of 25°. What is the normal force acting on the block?
**Explanation:**
To solve this problem, you need to determine the normal force exerted on the block by the inclined plane. The normal force is the perpendicular force that the surface exerts on an object in contact with it.
Given:
- The weight of the block (\(W\)) is 37 N.
- The angle of the incline (\(\theta\)) is 25°.
To find the normal force (\(N\)), we consider the component of the weight that acts perpendicular to the inclined plane. This can be calculated using the formula:
\[ N = W \cdot \cos(\theta) \]
Where:
- \(N\) is the normal force.
- \(W\) is the weight of the block, 37 N.
- \(\theta\) is the angle of the incline, 25°.
- \(\cos(\theta)\) is the cosine of the angle.
**Steps:**
1. Calculate \(\cos(25°)\).
2. Multiply the weight of the block by \(\cos(25°)\) to find the normal force.
This calculation will give the amount of the normal force acting on the block due to the inclined plane.](https://content.bartleby.com/qna-images/question/794f5517-509c-4604-8c86-39f37fec2cac/e794a781-8490-423f-a511-071775a56572/uyv0b78_processed.jpeg)
Transcribed Image Text:**Problem Statement:**
A 37 N block rests on an inclined plane with a slope of 25°. What is the normal force acting on the block?
**Explanation:**
To solve this problem, you need to determine the normal force exerted on the block by the inclined plane. The normal force is the perpendicular force that the surface exerts on an object in contact with it.
Given:
- The weight of the block (\(W\)) is 37 N.
- The angle of the incline (\(\theta\)) is 25°.
To find the normal force (\(N\)), we consider the component of the weight that acts perpendicular to the inclined plane. This can be calculated using the formula:
\[ N = W \cdot \cos(\theta) \]
Where:
- \(N\) is the normal force.
- \(W\) is the weight of the block, 37 N.
- \(\theta\) is the angle of the incline, 25°.
- \(\cos(\theta)\) is the cosine of the angle.
**Steps:**
1. Calculate \(\cos(25°)\).
2. Multiply the weight of the block by \(\cos(25°)\) to find the normal force.
This calculation will give the amount of the normal force acting on the block due to the inclined plane.
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