Organic Chemistry
9th Edition
ISBN: 9781305080485
Author: John E. McMurry
Publisher: Cengage Learning
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- Determine the following for the compound C6H15N a.) degrees of unsaturation b.) Assign the principal IR absorption bands above 1500 c.) draw the structure of the compound d.) label the protons on your structure with letters and assign them to peaks on the NMR spectrum.arrow_forwardConsider the product below a) Predict the 1H NMR spectrum for this molecule. Predict the multiplicity, integration and relative ppm b) Predict the 13C NMR spectrum and DEPT spectra. Use (+) for positivesignals, (-) for negative signals, and (X) for no signal in the DEPT NMR spectra.arrow_forward1B. Can 1H NMR spectroscopy be used to differentiate between the two compounds? Briefly explain why or why not. Predict the 1H NMR spectrum for each compound (include integration, multiplicity, and approximate chemical shift). Put it in data table format.arrow_forward
- III) Can 1H NMR spectroscopy be used to differentiate between the two compounds? Briefly explain why or why not. Predict the 1H NMR spectrum for each compound (include integration, multiplicity, and approximate chemical shift). For each set, be sure that you put them in a data table format!arrow_forwardBelow are the spectral data (IR, MS, 1H NMR, and 13C NMR) for an unknown organic compound. Examine the data carefully and answer the questions that follow.4a) There is only one set of signals above 1750 cm–1 in the IR spectrum. What functional group does this signal indicate? 4b) Combining information from the IR and NMR spectra, what major functional group is likely present? 4b) How many signals from sp3 carbons in 13C-NMR 4c) How many different proton chemical environments are in the molecule? 4e) Proposed structurearrow_forwardPlease show work 1. Compound A has molecular formula C5H10O. It shows three signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.1 ppm, a singlet of integral 3 at 2.14 ppm, and a quintet of integral 1 at 2.58 ppm. Suggest a structure for A and explain your reasoning.arrow_forward
- Than5 you!arrow_forwardDetermine the structure of a compound with the formula C11H15ClO2 based on the 1H NMR spectrum below. Based on its 13C NMR (DEPT) spectrum, it is evident that this molecule shows 9 signals including one methyl (CH3) and four methylene (CH2) units.arrow_forwardcompound with formula C9H10O. If the unknown has an IR absorption at 1690 cm–1 please tell me structure ??arrow_forward
- I have an NMR spectrum. There are 5 peaks. There is a doublet at 9.6 ppm (integrates to 2H) where aldehydes usually arise, don't know why there is a doublet. There is another doublet at 6.8 ppm, again integrating to 2H. There is a singlet at 4.5 ppm, integrating to 1H. There is a quartet at 3.4 ppm integrating to 2H, and lastly there is triplet at 1.2 ppm integrating to 3H. i recofnize the ethyl group but don't understand the peak at 9.6 unless it is not an aldehyde.arrow_forwardPredict (draw) the ¹H NMR and 13C NMR spectra for each molecule. Your illustration should include chemical shift, integration, and splitting (where appropriate). Label each signal in your spectrum a, b, c... etc and label the corresponding C/H atoms in each molecule. CIarrow_forwardHi there...can u please answer for question a, b & c. Thanks in advancearrow_forward
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