A wetted wall column of inside diameter (2 in) contains air and CO2 flowing at 3 ft/s. At a certain point in the column, the CO2 concentration in air is found to be 0.1 mol fraction. At the same point, the concentration of CO2 in the water at the water – air interface is estimated to be 0.005 mole fraction. The column operates at 10 atm and 25 °C. Considering a mass transfer through a stagnant layer (transfer of CO2 from air to water only), calculate the mass transfer coefficient and the mass flux at the point of interest, given that: The diffusivity of CO2 in air at 25 °C and 1 atm = 0.164 cm²/s The density of air at STP = 0.0808 lbm/ft³ The viscosity of air at 25 °C and 10 atm = 0.018×10-³ kg/m.s Hennery constant = 1640 atm / mol fraction the gas constant 0.082 atm.lit/mol.°K 0.833 Kčd = 0.023 DAB 0.333 Sh. No.= \PDAB- Im = 3.28 ft, 1ft = 12 in, 1 in= 2.54 cm, 1 kg= 2.2 Ibm

Find the diffusion coefficient of the CO and N2 gas couple at 580 K and 4 atm conditions.

Q2. Density and viscosity of a natural emulsion composed of 85% (by volume) water and 15% (by volume) of oil is 990 kg/m³ at 25°C and its viscosity is 1.8 cP. At this temperature density and viscosity of water are 1000 kg/m³ and 1 cP, respectively. Diameter of spherical oil droplets is 50 µm. a) Calculate density of oil droplets and then terminal velocity of oil droplets by deciding the flow regime. b) What can you say about the flow direction of the oil droplets? Show the flow direction and forces effective on the oil droplet by drawing an oil. c) At which time the emulsion is completely deformed (or separated into oil and water phases) if 200 liter emulsion exists in a cylindrical tank of which diameter is equal to the height of the emulsion? (Hint: Consider oil droplets as solid particles)

A multiple effect evaporator has a capacity to process 500 kg of solid caustic soda per day, when it is concentrating from 3% to 28% solids. The water evaporated in kg per day  is

A long glass capillary with a diameter of 0.1 cm is in contact with water on one side and dry air on the other. Water vapor evaporates from the side in contact with water and diffuses through the capillary to the other side. Using the following given data, calculate the rate at which water evaporates in this system in [g/s].Isothermal diffusion (20℃)Vapor pressure of water 17.5 mmHg (20℃)Water diffusivity 0.3 cm2/s (20℃)Dry air pressure 760 mmHgDural length 10 cmGas constant R=82 cm3atm/mol K18 g/mol molecular weight of water

please answer this asap

question in image.

1. Say we accidentally left the cover off of a test tube containing liquid benzene. The cylindrical test tube is 10 cm tall and 1.5 cm in diameter. Initially, the tube is 60% full of benzene. How long will it take for all of the benzene to evaporate (keep in mind that the flux will change as the benzene level falls). Assume transfer to the top of the tube is due only to molecular diffusion (so no convective transfer) and that the concentration at the top of the tube (= room air) is zero. The temperature is 25 °C, the pressure is 1 atm, the diffusion coefficient of benzene in air is 0.0962 cm²/s, the density of liquid benzene is 0.87 g/cm³, and its saturation vapor pressure at 25 °C is 0.126 atm.

Which of the following is the definition of diffusion coefficient? Select one: The rate of a molecule motion that being strongly dependent on and increasing exponentially with increasing temperature. The rate of an atomic motion that being strongly dependent on and increases exponentially with increasing temperature. The rate of an atomic motion that not dependent on and increases exponentially with decreasing temperature. The rate of a molecule motion that being strongly dependent on and increases exponentially with decreasing temperature.

30.19 Consider the device shown below that will be used to humidity an air stream. In the current process, air containing 1.0 mol% water vapor (species A) at 40°C and 1.0 atm enters the tube of 3.0 cm inner diameter at a velocity of 300 cm/s. A water- adsorbent material saturated with liquid water lines the inner surface of the tube. Water evaporates from this liner material as over it. There is no diffusion resistance of water vapor air passes Water adsorbent liner (1.0 mm thick, 0.6 g H,O/cm³ liner initially) Gas stream V =300 cm/sec D = 3.0 cm (tube) 1.0 atm, 40°C CA2 L = 8.0 m %3D through the liner material itself. The process is maintained at 40°C. The saturation vapor pressure of water is 55.4 mmHg at 40°C, At this temperature and 1.0 atm, the viscosity of air is 1.91 x 10¬4 g/cm · s and the density of air is 1.13x 10-3 g/cm³. a. What is the Schmidt number for this process? b. Develop a model, in final integrated form, to predict the concentration of water vapor exiting the tube.…