A well-known brokerage firm executive claimed that 80% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 400 people, 72% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is smaller than 80% at the 0.10 significance level. The null and alternative hypothesis would be: H0:p≤0.8H0:p≤0.8 H1:p>0.8H1:p>0.8  H0:μ=0.8H0:μ=0.8 1:μ≠0.8H1:μ≠0.8 H0:μ≤0.8H0:μ≤0.8 H1:μ>0.8H1:μ>0.8H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 H0:p≥0.8H0:p≥0.8 H1:p<0.8H1:p<0.8 H0:μ≥0.8H0:μ≥0.8 H1:μ<0.8H1:μ<0.8   The test is: left-tailed right-tailed two-tailed The test statistic is: __?___ (to 3 decimals) The p-value is: __?___  (to 4 decimals)

The National Institute of Mental Health published an article stating that in any one-year period, approximately 8.8% of American adults suffer from depression or a depressive illness. Suppose that in a survey of 2000 people in a certain city, 11.3% of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that city suffering from depression or a depressive illness is more than the 8.8% in the general adult American population. Test the relevant hypotheses using a 5% level of significance. Give answer to at least 4 decimal places. a. What are the correct hypotheses?  H0:       H1:          b.)  Based on the hypotheses, find the following: c.) Test Statistic =  d.)  p-value = e.)  Based on the above we choose to________________ f.) The correct summary would be:____________      that the true proportion of people in that city suffering from depression or a depressive illness is more than the percent in the general…

A college administrator is interested in determining the proportion of students who receive some sort of financial aid. Instead of examining the records for all students, the administrator randomly draws 120 students and finds that 48 of them are receiving financial aid. Use a 90% confidence interval to estimate the true proportion of students who receive financial aid.

A political scientist claims that 38% of first-year college students characterize themselves as being “moderate” or “middle of the road” as far as their political affiliation is concerned.   Believing this claimed value is too high, you survey a random sample of 400 first-year college students and find that 120 characterize themselves as being “moderate” or “middle of the road.”    Based on this information, what will the test statistic be? Choose the answer below that is closest to what you calculate, and try not to do a lot of rounding until you get to the very end of your calculations.   1. -0.3 2. -1.2 3. -2.6 4. -3.3 5. None of the other answer options are correct because the test statistic should be positive, not negative.

Spam: A researcher reported that 71.8 % of all email sent in a recent month was spam. A system manager at a large corporation believes that the percentage at his company may be 69%. He examines a random sample of 500 emails received at an email server, and finds that 365 of the messages are spam. Can you conclude that greater than 69% of emails are spam? Use both a=0.01 and a= 0.05 levels of significance and the critical value method with the table. Part 1 of 5 State the appropriate null and alternate hypotheses. Ho: P- .69 H1: p> .69 This hypothesis test is a right-tailed V test. Part 2 of 5 Find the critical values. Round the answers to three decimal places. For a=0.01 , the critical value is 2.326 For a=0.05 , the critical value is 1.645 Part: 2/5 Part 3 of 5 Compute the test statistic. Do not round intermediate calculations. Round the answer to two decimal places.

A 2018 Gallup poll found 20% of adults aged 18 - 29 years vape. Test the claim that the proportion of 18 - 29 year old people who vape has decreased at the 5% significance level. A July 2021 Gallup poll resulted in 17% of the 1,007 of people that age vape.

According to the most recent General Social Survey, 70% of adults watch TV nightly. A researcher believes that the proportion of college students who watch TV nightly is less than this. To test this claim the research samples 400 college students and finds that 276 watch TV nightly. At the 0.05 level of significance does this data provide evidence to suggest that the proportion of college students who watch TV nightly is less than 70%? What is the p-value for this hypothesis test? Round to three decimal places.

The National Institute of Mental Health published an article stating that in any one-year period, approximately 8.8% of American adults suffer from depression or a depressive illness. Suppose that in a survey of 2000 people in a certain city, 11.3% of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that city suffering from depression or a depressive illness is more than the 8.8% in the general adult American population. Test the relevant hypotheses using a 5% level of significance. Give answer to at least 4 decimal places. a. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) H0:    H1:     b. Based on the hypotheses, find the following: c. Test Statistic =   d. p-value =      e. Based on the above we choose to:_____________ f. The correct summary would be: ____________ that the true proportion of people in that city suffering from depression or a…