A water taxi carries passengers from harbor to another. Assume that weights of passengers are normally distributed with a mean of 180 lb and a standard deviation of 45 lb. The water taxi has a stated capacity of 25 passengers, and the water taxi was rated for a load limit of 3500 lb. Complete parts (a) through (d) below. a. Given that the water taxi was rated for a load limit of 3500 lb, what is the maximum mean weight of the passengers if the water taxi is filled to the stated capacity of 25 passengers? The maximum mean weight is 140 lb. (Type an integer or a decimal. Do not round.) b. If the water taxi is filled with 25 randomly selected passengers, what is the probability that their mean weight exceeds the value from part (a)? The probability is. (Round to four decimal places as needed.)

Please answer a and b

The blood pressure in millimeters was measured for a large sample of people. The average pressure is 140 mm, and the SD of the measurements is 20 mm. The histogram looks reasonably like a normal curv Use the normal curve to estimate the following percentages. Choose the answer that is closest to being correct. A 19.1% B 30.9% C 38.2% D 69.1% E 68.27% A The percentage of people with blood pressure between 130 and 150 mm. B The percentage of people with blood pressure between 140 and 150 mm. D The percentage of people with blood pressure over 150 mm.

2. A.) Find the 5-number summary for the data. B.) Is the data discrete or continuous?

The lengths of 40 leaves of a plant are measured correct to the nearest millimeter. Less than Cumulative frequency of the data obtained is represented in the following table. Which central tendency will be most appropriate for the data set? Length (mm) Less than cum freq Less than 127 3 127-135 136-144 17 145-153 29 154-162 34 163-171 38 172-180 40 O a. mode O b. mean O. midrange O d. median

The following table gives the mean velocity of planets in their orbits versus their mean distance from the sun. Note that 1 AU (astronomical unit) is the mean distance from Earth to the sun, about 93 million miles. Planet d = distance (AU) v = velocity (km/sec) Mercury 0.39 47.4 Venus 0.72 35.0 Earth 1 29.8 Mars 1.52 24.1 Jupiter 5.20 13.1 Saturn 9.58 9.7 Uranus 19.20 6.8 Neptune 30.05 5.4 Astronomers tell us that it is reasonable to model these data with a power function. (a) Use power regression to express velocity as a power function of distance from the sun. (Round regression parameters to two decimal places.) V = 21.41 x d -0.50 V = 21.41 x d-0.29 ° v = 29.73 x d¬0.50 V = 29.73 x d-0.73 v = 29.73 x d0.50 (b) Plot the data along with the regression equation. v V 50 50 H 50 50H 40 40 40 40 30 30 30 30 20 20 20 20- 10 10 10 10 d 10 15 20 25 30 d d 5 10 15 20 25 30 5 10 15 20 25 30 5 10 15 20 25 30 (c) An asteroid orbits at a mean distance of 3 AU from the sun. According to the power…

Answer for b c d