A vertical curve is needed to join to tangents; G₁=0% and G₂=-5%. Assuming a level grade (0%) for braking, and the AASHTO recommended values for deceleration and perception-reaction time, calculate the minimum length of curve (ft) needed to satisfy the safety criteria. The design speed is 70 mph. Response Feedback: G2-G₁ is negative, therefore a crest curve. A=5 SSD(0%)=726.8 ft If you assume S

A+1 percent grade intersects with a-2 percent grade at station (535+ 24.25) at an elevation of 300 t. (a) if the design speed is 65 mi/h, determine the minimum length (in t) of vertical curve using the rate of vertical curvature. (Assume the stopping sight distance is less than the length of the curve.) it (b) Using the length found in part (a), find the stations and elevations (in R) of the BVC and EVC and the elevation (in t) of each 100 t station. (In the table below, the first row corresponds to the BVC and the last row corresponds to the EVC. Round your elevations to at least one decimal place.) Station Elevation (t) 533 + 00 534 + 00 535 + 00 536 + 00 537 + 00 538 + 00 (c) Using the length found in part (a), find the station and elevation (in t) of the highpoint. station nlevation

A vertical curve is needed to join to tangents; G1=1% and G2=4%. Assuming a level grade (0%) for braking, and the AASHTO recommended values for deceleration and perception-reaction time, calculate the minimum length of curve (ft) needed to satisfy the safety criteria. The design speed is 60 mph.

A vertical curve is needed to join to tangents; G₁=1% and G2-4%. Assuming a level grade (0%) for braking, and the AASHTO recommended values for deceleration and perception-reaction time, calculate the minimum length of curve (ft) needed to satisfy the safety criteria. The design speed is 60 mph. Response Feedback: G2-G₁ is positive, therefore a sag curve. A=3 SSD(0%)=565.5 ft If you assume SL, Lmin-340 ft. SSD is greater than Lmin. The assumption is good.