A uniform thin rod of mass m = 2.9kg and length L = 1.3 m can rotate about an axle through its centerFour forces are acting on it as shown in the figure. Their magnitudes are F_{1} =; 8.5N, F_{2} = 3.5N; F_{3} = 13.5N and F 4 =19.5N.F 2 acts a distance d = 0.16 m from the center of mass. Part (a) calculate the magnitude t1 of the torque due to for e f1, in newton meters Part b :calculate the magnitude t2 of rhe torque due to foce f2 in newton meters Part c calculate the magnitude t3 of the torque due to force f3 in newton meters Part d calculate the magnitude t4 of the torque due to force f4 in newton meters Part eCalculate the angular acceleration a of the thin rod about its center of mass in radians per square second

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter15: Fluid Mechanics
Section: Chapter Questions
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A uniform thin rod of mass m = 2.9kg and length L = 1.3 m can rotate about an axle through its centerFour forces are acting on it as shown in the figure. Their magnitudes are F_{1} =; 8.5N, F_{2} = 3.5N; F_{3} = 13.5N and F 4 =19.5N.F 2 acts a distance d = 0.16 m from the center of mass. Part (a) calculate the magnitude t1 of the torque due to for e f1, in newton meters Part b :calculate the magnitude t2 of rhe torque due to foce f2 in newton meters Part c calculate the magnitude t3 of the torque due to force f3 in newton meters Part d calculate the magnitude t4 of the torque due to force f4 in newton meters Part eCalculate the angular acceleration a of the thin rod about its center of mass in radians per square second Let the counter-clockwise direction be positive
F₂ 2
F
3
45°
60°
Ja
F
4
F₁
Otheexpe
Transcribed Image Text:F₂ 2 F 3 45° 60° Ja F 4 F₁ Otheexpe
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