A uniform steel rod of length 0.6 m and mass 1.6 kg has two point masses on each end. The point mass on the left end is of 1.3 kg and the one on the right end is 3.5 kg.  Calculate the moment of inertia of the system about an axis perpendicular to the rod, and passing through the center of mass of this system.

Problem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass. Part (a) First calculate the moment of inertia (in kg m2) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.11 m. sin() cos() tan() 7 8 9 HOME cotan() asin() acos() E 4 5 atan() acotan() sinh() 1 3 cosh() tanh() cotanh() END ODegrees O Radians Vol BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Part (b) Now calculate the moment of inertia of the skater (in kg m?) with their arms extended by assuming that each arm is 5% of the mass of their body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being rotated at the ends.

Can you please help me solve this..   Three masses A = 3kg , B = 4kg and C = 5kg are connected by rods of negligible mass to form an equilateral triangle of side 8m as shown. Determine the individual moment of inertia and total moment of inertia of the system about axis XY.   Solve for: (a) Total moment of inertia of the system (b) Moment of inertia of object C (in kg-m^2) (c) Moment of inertia of object B (in kg-m^2) (d) Moment of inertia of object A (in kg-m^2)   •Pls answer with complete and detailed solution (3 DECIMAL PLACES all final answers with correct units) •Sketch an illustration/diagram with labels (this is a must; for a better understanding)   Thank you I will give your answer a LIKE for helping me...

A 139-kg platform-oriented horizontally consists of a uniform disk of radius 1.85 m and can rotate about the vertical axis through its center. A 63.3-kg person stands on the platform at a distance of 1.17 m from the center and a 27.5-kg dog sits on the platform near the person, 1.39 m from the center. Find the moment of inertia of this system, consisting of the platform and its population, with respect to the axis.

As a physics demonstration, a special bowling ball is made so that it can be rotated about its center of mass to get a feel for how "big" a moment of inertia of 1 kg⋅m2 is. The average bowling ball has a weight of 15.4 lbs and a circumference of 26.3 inbut it does not have a moment of inertia equal to 1 kg⋅m2.Since the sporting goods manufacturer has no understanding of how "big" 1 kg⋅m21  is, calculate the diameter ? demo of the demo bowling ball, in inches, that it will need to manufacture. Assume that bowling balls are solid, with a constant density.   D of demo required in inches.

Three masses, each m = 12 kg, are located at the corners of an equilateral triangle. Calculate the moment of inertia of the system about an axis running through one of the point masses perpendicular to the plane of the triangle. The length of one side of the triangle is 0.94 m

The moment of inertia of the lower leg and foot about an axis through the knee joint is 0.23 kgm^2. What is the moment of inertia of the leg and foot about the knee joint if a 0.82 kg shoe is worn on the foot? Assume that the shoe's mass is all concentrated in one point 40 cm from the knee. (please report to two decimal places)

Consider a homogeneous rigid body with a non-uniform distribution of mass. The body is rotating about a fixed axis. Which of the following statements about the moments of inertia is correct? A) The principal axes of inertia will coincide with the axis of rotation. B) The moment of inertia about the axis of rotation will be the smallest possible. C) The moment of inertia about any axis parallel to the axis of rotation will be constant. D) The moment of inertia tensor will be diagonal, with all diagonal elements distinct. Choose the correct option and justify your choice.

A 109 kg horizontal platform is a uniform disk of radius 1.57 m and can rotate about the vertical axis through its center. A 62.9 kg person stands on the platform at a distance of 1.15 m from the center, and a 28.7 kg dog sits on the platform near the person 1.39 m from the center. Find the moment of inertia of this system, consisting of the platform and its population, with respect to the axis. moment of inertia: kg · m²

A thin 7.0-kgkg wheel of radius 35 cmcm is weighted to one side by a 1.20-kgkg weight, small in size, placed 21 cmcm from the center of the wheel. Part A. Calculate the position of the center of mass of the weighted wheel (distance from the center of the wheel). Part B. Calculate the moment of inertia about an axis through its cmcm, perpendicular to its face.