Problem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass.**Part (a)** First calculate the moment of inertia (in kg·m²) when the skater has their arms pulled inward by assuming they are a cylinder of radius 0.11 m.\( I_b = \) [Input field]Below the input field, there is an interactive calculator with trigonometric and hyperbolic functions, constants, and a number pad. Functions include:- Trigonometric: \( \sin() \), \( \cos() \), \( \tan() \), \( \cotan() \), \( \asin() \), \( \acos() \), \( \atan() \), \( \acotan() \)- Hyperbolic: \( \sinh() \), \( \cosh() \), \( \tanh() \), \( \cotanh() \)The calculator has options for calculating in Degrees or Radians, and buttons for basic operations and navigation.**Part (b)** Now calculate the moment of inertia of the skater (in kg·m²) with their arms extended by assuming that each arm is 5% of the mass of their body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being rotated at the ends.

Answered: Image /qna-images/answer/c826a4a3-9636-4612-b5f3-dba9c881ab11.jpg

Problem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass. Part (a) First calculate the moment of inertia (in kg-m) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.11 I = sin() cos() tan() 9 HOME cotan) asin() acos() E 4 5 6 atan() acotan() sinh() 1 2 cosh() tanh() cotanh() END + ODegrees O Radians vol BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Part (b) Now calculate the moment of inertia of the skater (in kg m2) with their arms extended by assuming that each arm is 5% of the mass of eir body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being rotated the ends.

Problem 3: Suppose we want to calculate the moment of inertia of a 65.5 kg skater, relative to a vertical axis through their center of mass. Part (a) First calculate the moment of inertia (in kg-m) when the skater has their arms pulled inward by assuming they are cylinder of radius 0.11 I = sin() cos() tan() 9 HOME cotan) asin() acos() E 4 5 6 atan() acotan() sinh() 1 2 cosh() tanh() cotanh() END + ODegrees O Radians vol BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Part (b) Now calculate the moment of inertia of the skater (in kg m2) with their arms extended by assuming that each arm is 5% of the mass of eir body. Assume the body is a cylinder of the same size, and the arms are 0.825 m long rods extending straight out from the center of their body being rotated the ends.