A uniform solid cylinder is initially at rest at the top of a ramp of height 1.5 m. If the cylinder rolls down this ramp without slipping, what will be its speed at the bottom? Why don't you need to consider the work done by friction? Explain your reasoning in detail

While spinning down from 500.0 rpm to rest, a solid uniform disk does 51 KJ of work. If the radius of the disk is r=400mm what is it's mass?.

A hollow sphere is released from rest at the top of the ramp at the height of 0.21 m. The hollow sphere rolls down the ramp (height at the bottom is 0.05m) to a distance of 1.00 m in 1.192 seconds. The angle of the incline is 15 degrees. There is only potential energy at the top and only Kinetic energy at the bottom of the ramp. Please calculate the linear speed at the bottom of the ramp. Assume that the acceleration is not 9.8 m/s2. Find the value for the height by the difference in height from where the sphere was released to where the bottom is located.  Calculate the translation speed of the hollow sphere at the bottom of the ramp using conservation of energy equations.

The figure shows a rigid assembly of a thin hoop (of mass m = 0.24 kg and radius R = 0.16 m) and a thin radial rod (of length L = 2R and also of mass m = 0.24 kg). The assembly is upright, but we nudge it so that it rotates around a horizontal axis in the plane of the rod and hoop, through the lower end of the rod. Assuming that the energy given to the assembly the nudge is negligible, what is the assembly's angular speed about the rotation axis when it passes through the upside-down (inverted) orientation? Number i Rod Hoop ! Rotation axis Units

A rod of mass m and length L is hinged with a frictionless hinge at one end. The moment of inertia about the center of mass is -m L². Attached to the end of the rod opposite to the hinge there is a mass of magnitude 2 m. The rod is released from rest in the horizontal 12 position. m 2m What is the speed of the mass 2 m when the rod passes through the vertical position? Consider the mass at the end of the rod to be a point particle. 1. ||T2m|| L 2. ||T2m|| = VgL 3. ||T2m| : 5 g L V %3D 2 15 g L V 4. ||T2m|| = 7 3gL 5. ||T2m|| 2gL 6. ||T2m| 5

A person opens a 7.25 kg door by applying a force of 12.5 N perpendicular to it at a point 0.85 m from the hinges. The door measures 2,25 m high and 1.15 m wide. Find the angular acceleration of the door. If the door is pushed wide open by 75,0° in 2.0 s, find the work done on the door and the power delivered to the door.

Pls answer with handwritten solutions

A rotating flywheel can be used to store energy. If it is required to store 1.00 × 106J of energy when rotating at, ω, 400 rad/s, what is the moment of inertial of the wheel inkg∙m2?A) 6.25B) 12.5C) 25.0D) 50.0

The figure shows a thin rod, of length L = 2.20 m and negligible mass, that can pivot about one end to rotate in a vertical circle. A heavy ball of mass m = 8.10 kg is attached to the other end. The rod is pulled aside to angle 00 = 8° and released with initial velocity V 0. (a) What is the speed of the ball at the lowest point? (b) Does the speed increase, decrease, or remain the same if %3D the mass is increased? 3.

The rigid body shown in the figure consists of three particles connected by massless rods. It is to be rotated about an axis perpendicular to its plane through point P. If M = 0.41 kg, a = 35 cm, and b = 53 cm, how much work is required to take the body from rest to an angular speed of 5.8 rad/s? M 2M Number Units J