College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Question
Transcribed Image Text:Find the speed of the particle at B by modeling it as a nonisolated system in terms of energy.
SOLUTION
Categorize The problem statement tells us that the charge is a nonisolated system for energy. The electric force, like
any force, can do work on a system. Energy is transferred to the system of the charge by work done by the
---Select---
+ force exerted on the charge. The initial configuration of the system is when the particle is at rest at A,
and the final configuration is when it is moving with some speed at B.
Analyze
Write the appropriate reduction of the conservation of energy equation,
ΔΚ + Δυ + ΔΕ
= W + Q + TMw + TMT + TET + TER, for the system of the charged particle:
int
W= ΔΚ
Replace the work and kinetic energies with values appropriate for this situation. (Use the following as necessary: F.,
Ax, E, and m.)
e'
FAx = KB - KA
2
-mv? - 0 → v, =
Substitute for the electric force F and the displacement Ax. (Use the following as necessary: E, m, d, and q.)
Finalize The answer to part (b) is the same as that for part (a), as we expect. This problem can be solved with
different approaches. We saw the same possibilities with mechanical problems.
EXERCISE
In an experiment similar to the setup described in the Example, a positively charged particle of mass m is released from
rest at the surface of the positive plate. The velocity of the particle at the negative plate is 1.30 x 105 m/s. If the electric
field magnitude is 6.00 x 103 N/C, the distance between the two plates is 5 cm, and the charge on the particle is 3e, what
is the particle's mass (in kg)?
Transcribed Image Text:A uniform electric field E is directed along the x-axis between parallel plates of charge separated by a distanced as shown in the figure. A positive point charge q of mass m is released from rest at a point A next to the
positive plate and accelerates to a point B next to the negative plate.
A positive point charge q in a
uniform electric field E undergoes
constant acceleration in the
direction of the field.
+
+
= 0
B
d
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- In a typical television or in an older computer picture tube (CRT), the electrons that strike the screen to form an image are accelerated between two charged plates that have a potential difference of 2.5×104 V. The plates are separated by a distance of 1.3 cm. Assuming that there is a uniform electric field between the plates, calculate the strength of the field.arrow_forwardCharge q, = 2.50 nC is at x, = 0 and charge q, = 6.00 nC is at x, = 4.00 m. At what point between the two charges is the electric field equal to zero? (Enter the x coordinate in m.) HINT Write an expression for the net electric field as a function of position, x, in the region between the two charges. (Don't forget that the electric field is a vector, so direction is important!) Set this expression equal to zero and solve for the variable x using the quadratic equation. Click the hint button again to remove this hint. marrow_forwardA pair of unlike charges equal in magnitude and separated by a small distance is known as a dipole. Such a pair is situated on the x axis at equal distances from the origin as shown in the figure below. Use the direction rosette to answer the questions. ΧΑ 8 + * D E B 3 +q -9 5 9 zero magnitude (a) What is the direction of the net electric field at location C due to both charges? 5 X Did you consider the symmetry of the situation? What is the net contribution to the field from the y components of the field from each charge? (b) What is the direction of the net electric field at location D due to both charges? ---Select--- v (c) What is the direction of the net electric field at location E due to both charges? ---Select--- ✓ Additional Materials Reading 7arrow_forward
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