College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
An electron is placed in a uniform electric field of 32nN/C directed north created by two horizontal parallel plates that are 131fm apart. The electron accelerates from rest, starting at the negative plate. What is the net force and acceleration acting on the electron? How long did it take the electron to get from one side of the plate to the other?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by stepSolved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle with the same mass as an electron but the opposite charge (+e). If a positron is accelerated by a constant electric field of magnitude 271 N/C, find the following. (a) Find the acceleration of the positron. m/s² (b) Find the positron's speed after 6.50 x 10-9 s. Assume that the positron started from rest. m/sarrow_forwardplease solve asap.arrow_forwardAn electron, initially at rest is placed in an electric field of 5?105 ?∕? directed west. What is the acceleration of the electron due to the electric field? Group of answer choices 4.79x10^13 m⁄s^2 4.79x10^-13 m⁄s^2 8.78x10^-16 m⁄s^2 8.78x10^16 m⁄s^2arrow_forward
- Newer automobiles have filters that remove fine particles from exhaust gases. This done by charging the particles and separating them with a strong electric field. Consider a positively charged particle + 1.5uC that enters an electric field with strength 4 x 10^6 N/C. The particle is traveling at 15 m/s and has a mass of 10^-9 g. What is the acceleration of the particle ? (Enter the magnitude only) 2.) what is the direction of the acceleration of the particle relative to the electric field?arrow_forwardA positively charged particle of mass 1.92 x 10-27 kg initially moves left to right long the x axis at a speed of 4.02 x 103 m/s. It moves into an electric field, which points in the negative x direction, and travels a distance of 0.41 m before coming to rest. What acceleration magnitude does the particle experience? (Ignore gravity) Round your answer to 2 decimal places.arrow_forwardOn a typical clear day, the atmospheric electric field points downward and has a magnitude of approximately 110 N/C. Compare the gravitational and electric forces on a small dust particle of mass 3,1 x 10 g that carries a single electron charge. 1.1134 What is the acceleration (both magnitude and direction) of the dust particle? (Enter the magnitude in m/s.) magnitude m/s direction downward varrow_forward
- A simple and common technique for accelerating electrons is shown in the figure below, where a uniform electric field is created between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electron if the field strength is 3.45 x 104 N/C. m/s² (b) Why will the electron not be pulled back to the positive plate once it moves through the hole? O The force of gravity is too strong. O There is no field outside the plates. O The other side of the positive plate also has a negative charge.arrow_forwardHelp me answer this question please. An electron is projected horizontally at a speed of 2.5 x 10*6 m/s between two plates. metal parallel I = 7.5 cm in length as shown in the figure below. The greatness of electric field is 130 N/C. Determined : a) Acceleration of the electron b) The time it takes to escape from the metal plates c) The final vector velocity of the electron as it escapes from the platesarrow_forwardThree charges are at the corners of an equilateral triangle, as shown in the figure below. Calculate the electric field at a point midway between the two charges on the x-axis. (Let q1 = 2.50 ?C,q2 = 6.00 ?C,and q3 = −2.50 ?C.)arrow_forward
- In the ever popular game from the future, Electrodisc, players can score double points by pushing a disc into another disc with the electric field generated by a third disc. The discs are by regulation 1 kg. All discs have the same shape and are made of the same conducting material. In the figure below, disc 1 is held in place, and disc 2 is held stationary 4.1 m from disc 1 by a player. The player then releases disc 2. 10 m. F12 What is the initial magnitude of the acceleration imposed on the second disc? The charge on the first disc is 1.7 mC. The charge on the second disc is 1.7 mC. The charge on the third disc is neutral. m/s² Later, discs 2 and 3 touch and charge is exchanged. How much charge is exchanged once the charges on each disc reach an equilibrium? mC After charge is exchanged, what is the direction of the force on disc 3 due to disc 2? O toward the left O toward the right O upward O downwardarrow_forwardA proton is projected in the positive x direction into a region of uniform electric field E = (-6.20 × 105) ↑ N/C at t = 0. The proton travels 7.90 cm as it comes to rest. (a) Determine the acceleration of the proton. m/s² magnitude direction -X (b) Determine the initial speed of the proton. m/s magnitude direction +X ✓ ✓ (c) Determine the time interval over which the proton comes to rest.arrow_forward= An electric charge q₁ 38 mC is located at the origin of the (x,y) plane, while another charge q₂ = 6 mC is placed at the position x₂ = 1.6 m, see the picture below. At what position should a third charge q3 be placed so it experiences no net force? y q1 X₁₁=0 The new position of the third charge, x3, new 92 = $2 The position of the third charge, x3 : Solve the same problem with all the same values, but with the opposite sign of the second charge: 9₁ = 38 mC, q2 = -6 mC, and x2 = 1.6 m. X Units Select an answer ✓ Units Select an answer ✓arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON
Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley
College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON