A trapezoidal is shown below. The particulars of the channel are as such:• Side slopes are 1 in 0.5 m.Manning's n = 0.015• Slope of channel is 1 m in 1 km0.5ba. Using a value of 5 m for the bottom width and a normal depth of flow of 2 m, determinthe following:i.ii.iii.DischargeMean VelocityReynolds No.b. If the discharge were 35 m³/s and bottom width was 5m, what would the normal depthof flow be? All other conditions remain the same.

Note:- Hi! Thank you for the question As per the honor code, We’ll answer the first question since…

A trapezoidal is shown below. The particulars of the channel are as such: • Side slopes are 1 in 0.5 m. • Manning's n = 0.015 • Slope of channel is 1 m in 1 km 0.5 a. Using a value of 5 m for the bottom width and a normal depth of flow of 2 m, determi the following: i. Discharge ii. iii. b Mean Velocity Reynolds No.

A trapezoidal is shown below. The particulars of the channel are as such: • Side slopes are 1 in 0.5 m. • Manning's n = 0.015 • Slope of channel is 1 m in 1 km 0.5 a. Using a value of 5 m for the bottom width and a normal depth of flow of 2 m, determi the following: i. Discharge ii. iii. b Mean Velocity Reynolds No.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Variation of water depth (y) in a gradually varied open channel flow is given by the first order differential equation In(y) dy dx = 10 1-e 3 In (y) -3 ln 250-45e Given initial conditions: y (x = 0) = 0.8 m. The depth (in m, up to three decimal places) of flow at a downstream section at x = 1 m from one calculation step of Single Step Euler Method is
Q (5-2)/ Water flows uniformly in an earth rectangular cross section open channel. Data available are: (45) Bed width of the channel B= 20 y (m), longitudinal slope of bed level of the channel S. 0.0001, n = 0.017 {s/m(13)) and water flow rate Q=150 - (m³/s). Calculate values of the followings: 1- Bed width of the channel B. 2- Water flow depth in the channel y. 3- Fruid Number Fr. LA (ar) 000001-0001 * 001- antarts out to ystoming bato WA +5=(3+1) +8 ANSWER/ A=0.05B², P= 1.1 B, B = 53.42 (m), y = 2.67 (m), A = 142 (m²), v= 1.05 01100021 (m/s), Fr= 0.2 less than 1. Flow is sub-critical (slow flow). ply to 'm) 016012-re.fx 000seas
Water flows in a trapezoidal channel with side slope 1V:3H, bottom width of 16 ft and water depth of 4.5ft. The channel bottom drops 0.1ft every 100ft. Length, n=0.015. Show Complete Solutiona. Compute the velocity in ft/s (using Manning, Kutter)b. Compute the flow rate in ft3/s (using Manning, Kutter)
What does a negative flow rate mean?A. This value is incorrect and shall be indicative of wrong computation.B. The head loss is actually a head gain.C. The correct direction is opposite of the assumed direction of the flow rate.D. None of the above.
23. Water flows in a triangular channel at a depth of 0.90 m. A hydraulic jump occurs at a depth just downstream of the jump is measured to be 1.8 m. The apex angle is 90°. Calculate the discharge of the triangular channel (apex down). 24.If water is flowing in a rectangular channel 30 ft wido Trith tho digoh
Design examples Use Kirschmer's equation_to find the head loss through a rectangular bar screen used in treatment plant, if the bar width is 15 mm and spacing is 25 mm. Assume that the width of channel (w) equal two times of water depth. Use Q = 0.6 m/s, approach velocity = 0.6 m/s and theta = 60°.
2.1 In a rectangular channel F, and F, are the Froude numbers corresponding to the alternate depths of a certain discharge. Show that F 2/3 2+F² 2+F²
The water velocity in the channel shown in the figure has a velocity distribution across the vertical section equal to u = umax (y/d)!/2. What is the discharge in the channel if the water is 2 m deep (d = 2 m), the channel is 5 m wide, and the maximum velocity is 3 m/sWhat is the mean velocit max (y\1/2 u = u. maxd d
A trapezoidal channel has a bottom width of 6 m and side slopes of 2 horizontal to 1 vertical. The depth of flow is 1.2 m and the discharge is 20.40 cu.m./s. If n=0.015, what is the slope of the channel? Select one: O a. 0.00165 O b. 0.00152 O c. 0.00108 O d. 0.00182
A trapezoidal channel with the dimensions shown in the figure below is laid on a slope of 0.003 ft/ft. The Manning's n value for the channel is 0.034, and the rate of flow through the channel is 866 cfs. Calculate and plot the water surface profile from the point where the channel ends (assume a free outfall) to the point where y is less than or equal to 0.9 yn. ملة 1.5 B 20' 1.5
3. Two adjacent communities are represented by the simplified system shown below. Determine the water consumption and pressure at A if the pump pressure is 425 kPa, and the consumption and pressure at B are 50 L/s and 275 kPa respectively. Draw the HGL. Note, the elevation of the pump and communities A and B are provided in m. B 310.00 305.00 Pump 300.00 4000.00 400 Ø 1000.00 300 Ø C = 100 C=140
Determine the other alternated depth in meters of the rectangular channel section (width = 3 meters) with a different flow rate. Section 1 depth = 5m Section 1 flow rate = 15m3/s Section 2 flow rate = 15 m3/s Pls answer