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- Two point charges are located at two of the vertices of a right triangle, as shown in the Figure16.4. If a third charge −2q is brought from infinity and placed at the third vertex, what will itselectric potential energy be? Use the following values: a = 0.16 m; b = 0.45 m, and q = 2.0 × 10−5C.arrow_forwardWhat is the potential difference between the points (10 cm, 5.0 cm) and (5.0 cm , 5.0 cm) if a point charge Q = 20 nC is at the origin?arrow_forwardGiven two particles with Q = 2.90-μC charges as shown in the figure below and particle with charge q = 1.32 x 10-18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞.) y the. x = -0.800 m 0 x=0.800 m Q (a) What is the net force (in N) exerted by the two 2.90-μC charges on the charge q? (Enter the magnitude.) N (b) What is the electric field (in N/C) at the origin due to the two 2.90-μC particles? (Enter the magnitude.) N/C (c) What is the electrical potential (in kV) at the origin due to the two 2.90-µC particles? kV (d) What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 2.90-μC particles?arrow_forward
- Why is it convenient to use the potential to calculate the electric field? Why not just calculate the electric field directly?arrow_forwardIn Figure (a), we move an electron from an infinite distance to a point at distance R = 9.20 cm from a tiny charged ball. The move requires work W = 2.75 x 10-13 J by us. (a) What is the charge Q on the ball? In Figure (b), the ball has been sliced up and the slices spread out so that an equal amount of charge is at the hour positions on a circular clock face of radius R = 9.20 cm. Now the electron is brought from an infinite distance to the center of the circle. (b) With that addition of the electron to the system of 12 charged particles, what is the change in the electric potential energy of the system? (a) Number i (b) Number i |-R- (a) Units Units (b)arrow_forwardOpgave 25.32: (a) A sheet with charge Q uniformly distributed over its area A is surrounded by a dielectric. Show that the sheet creates a uniform electric field at nearby points and derive an expression for the magnitude of the field. (b) Two large sheets of area A, carrying opposite charges of equal magnitude Q, are a small distance d apart. Show that they create a uniform electric field in the space between them and derive an expression for the magnitude of the field. (c) Assume the negative plate is at zero potential. Derive an expression for the potential at the positive plate. (d) Derive an expression for the capacitance of the pair of plates.arrow_forward
- Please type clear thank youarrow_forwardTwo point charges have a total electric potential energy of -24 J, and are separated by 29 cm. If the total charge of the two charges is 45 μC, what is the charge, in μC, on the positive one? What is the charge, in μC, on the negative one?arrow_forwardLevitation: The largest electric field strength you can create in air before dielectric breakdown (a spark) occurs is about 3.0 x 10°V/m. Suppose you created an electric field with this strength – pointing directly upward – between a set of parallel plates that are 9.9cm apart. You want to use this system to levitate water droplets with a mass of 1.8g. (a) How much charge would you have to put on a droplet to make it levitate? (b) Suppose that 43 charged droplets are levitating and the field strength suddenly drops by 24 percent, to about 2.3 x 106 V/m, how quickly would the droplets accelerate? Earrow_forward
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