College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A thin lens has a focal length of25.0 cm.(a) Find the location of the image formed by the lens when an object is placed at distance26.2 cmin front of the lens.(b)Describe the image (real/virtual, upright/inverted, enlarged/reduced). (c)Findthe location of the image formed by the lens when an object is placed at distance 24.0cm in front of the lens.(d) Describe the image (real/virtual, upright/inverted, enlarged/reduced).
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- 1) Calculate the magnification of the 36-in refractor at Lick Observatory on Mount Hamilton near San Jose, California. The focal lenght of the objective lens is 17.37m, and the focal lenght of the eyepiece is 22 mm. (Express your answer to three significant figures.) 2) What is the significance of the negative sign in the magnification equation? a) The image is inverted when viewed in the eyepiece. b) The image is upright when viewed in the eyepiece.arrow_forwardA microscope has an eyepiece with a focal length of 18.0 mm, and an objective with a focal length of 8.00 mm. Thelenses are separated by 19.7 cm. A) If the final image is located infinitely far away, where is the object located? B) What is the total magnification?arrow_forwardAn object is located 15.8 cm to the left of a diverging lens having a focal length f = −36.2 cm. (a) Determine the location of the image. distance cm location ---Select--- to the right of the lens to the left of the lens (b) Determine the magnification of the image.(c) Construct a ray diagram for this arrangement.arrow_forward
- = A leaf of length his positioned d below. Leaf d 70.3 cm in front of a converging lens with a focal length of 34.0 cm. An observer views the image of the leaf from a position 1.26 m behind the lens, as shown in the figure 1.26 m (a) What is the magnitude of the lateral magnification (the ratio of image size to the object size) produced by the lens? (b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the leaf directly?arrow_forwardIn a two-lens system, the focl length of the lens is f1 = 4.00 cm, and that of then lens 2 is f2 = 8.00 cm. The distance between the lenses is 16 cm. If an object O is 2.00 cm high and is placed 6.00 cm in front of the lens 1, where is the final image through the two-lens system?arrow_forwardUse the worked example above to help you solve this problem. The near point of a patients eye is 50.0 cm. (a) What focal length must a corrective lens have to enable the eye to see clearly an object 29.9 cm away? Neglect the eye-lens distance. 69.0 x cm (b) What is the power of this lens? +1.45 X diopters (c) Repeat part (b), taking into account the fact that, for typical eyeglasses, the corrective lens is 2.00 cm in front of the eye. +2.21 X dioptersarrow_forward
- An object is placed 30 cm from the center of a 50-cm-focal-length converging lens. (a) Draw a ray diagram and show where the image is located. (Your diagram MUST be legible and correct to earn points). (b) Find the location of the image analytically using the thin lens equation. (c) What is the magnification? (Pay attention to the signs).arrow_forwardAn object is placed a distance of 7.02f from a converging lens, where f is the lens's focal length. (Include the sign of the value in your answers.) (a) What is the location of the image formed by the lens? d; = (b) Is the image real or virtual? O real O virtual (c) What is the magnification of the image? (d) Is the image upright or inverted? O upright O invertedarrow_forward(a) For a diverging lens (f = - 16.0 cm), find the image distance for an object that is 16.0 cm from the lens. (b) Determine the magnification of the lens.arrow_forward
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