A tensile test was performed to find the stress-strain curve of a metal sample.Here are the results provided by the tensile testing machine .Suppose the results are free of errors. Elongation, 0 AL (cm) Applied force , F(N) 4.086 5.448 2.724 6.81 1.362 55571.1 61710.1 52930.5 68018.1 39498.3 Additional information: Lo: the length of the extensometer Lo = 5.42 cm A= 5.342 Questions : a) At. Using the 0.2% yield strength method, calculate the tensile strength of the metal sample. b) Find the modulus of resilience of the material under test. c) Calculate the allowable load for an object made of this metal using the parameters following: * Maximum stress: elastic limit Cross section: 10 mm2 Safety factor (or margin): 7 Calculate numerically with a minimum of four decimal places.

A tensile test was performed to find the stress-strain curve of a metal sample.Here are the results provided by the tensile testing machine .Suppose the results are free of errors. Elongation, 0 AL (cm) Applied force , F(N) 4.086 5.448 2.724 6.81 1.362 55571.1 61710.1 52930.5 68018.1 39498.3 Additional information: Lo: the length of the extensometer Lo = 5.42 cm A= 5.342 Questions : a) At. Using the 0.2% yield strength method, calculate the tensile strength of the metal sample. b) Find the modulus of resilience of the material under test. c) Calculate the allowable load for an object made of this metal using the parameters following: * Maximum stress: elastic limit Cross section: 10 mm2 Safety factor (or margin): 7 Calculate numerically with a minimum of four decimal places.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The stress-strain data from a tensile test on a cast-iron specimen are € (10-3) 0 0.20 0.44 0.80 1.0 1.5 2.0 26 32 40 46 49 54 NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 2.8 3.4 4.0 5.0 a (kpsi) 0 5 10 16 19 Determine the tangent modulus, E, at a value of a=0 psi. 106 psl. The tangent modulus, Eis X
a . Sketch stress strain curve if the result shown in table represent the force and extension happened in steel, and show Mechanical properties that we get from tensile test on curve? (10p)Note : Lo=80 mm , Do=10 mm , use excel to plot the curve ExtensionLoad(mm) (N)0 0.900.83 4694.341.67 4831.412.50 4781.083.33 4918.834.17 4926.585.00 5257.075.83 5437.016.66 5575.888.33 5775.189.16 5847.5210.83 5965.4111.67 6010.5312.50 6042.5713.33 6072.2614.16 6092.9315.00 6113.2416.67 6140.3617.50 6146.3718.33 6148.1419.16 6149.1725.00 5940.2125.83 5675.3326.67 4725.52b. What is meant by modulus of rigidity? if it increases what does happen to material? (2p)
The following stress-strain curve was prepared based on a tensile test of a specimen that had a circular cross-section. The gage diameter of the specimen was 0.25 inches and the gage length was 4 inches. The stress scale of the stress-strain diagram is given with the factor a = 10 ksi. Estimate: (a) The modulus of elasticity. (b) The ultimate strength. (c) The yield strength (0.2% offset). (d) The percent elongation at fracture. 2013 Michael Swanbom STRESS VS. STRAIN BY NC SA 7a bat Sat 2at at 0.05 STRAIN 0.01 0.04 0.06 0.08 0.02 0.03 0.07 0.09 STRESS
Stress Strain Diagram The Data shown in the table have been obtained from a tensile test conducted on a high-strength steel. The test specimen had a diameter of 0.505 inch and a gage length of 2.00 inch. Using software. plot the Stress-Strain Diagram for this steel and determine its: A= TTdT(050s A %3D 1. Proportional Limit, 2. Modulus of Elasticity, 3. Yield Strength (SY) at 0.2% Offset, 4. Ultimate Strength (Su), 5. Percent Elongation in 2.00 inch, 6. Percent Reduction in Area, 7. Present the results (for Steps 1-6) in a highly organized table. e Altac ie sheet (as problelle 4 A = 0.2.002 BEOINNING of the effort Elongation (in) Elongation (In) Load Load #: #3 (Ib) (Ib) 1 0.0170 15 12,300 0.0004 1,500 16 12,200 0.0200 0.0010 3. 3,100 17 12,000 0.0275 0.0016 4,700 18 13,000 0.0335 5. 6,300 0.0022 19 15,000 0.0400 0.0026 6. 8,000 20 16,200 0.055 0.0032 9,500 21 17,500 0.0680 0.0035 8. 11,000 22 18,800 0.1080 0.0041 11,800 23 19,600 0.1515 0.0051 24 20,100 0.2010 10 12,300 0.0071 25…
3. A cylindrical specimen of cold-worked copper has a ductility, %EL. If its cold-worked radius is d, what was its radius before deformation? Use %EL=25%; d = 10mm Ductility (%EL) 70 60 50 40 30 20 Brass 1040 Steel 10 Copper 0 0 10 110 20 30 40 50 60 70 Percent cold work
6. The following engineering stress-strain data were obtained for 0.2% C plain carbon steel. (a) Plot the engineering stress-strain curve (b) Determine the ultimate tensile strength for the alloy (c) Determine the percent elongation at fracture (d) Plot the true stress-strain curve Engineering strain, in./in. Engineering stress, ksi 30 0.001 55 0.002 60 0.005 68 0.01 72 0.02 74 0.04 75 0.06 76 0.08 75 0.1 73 0.12 69 0.14 65 0.16 56 0.18 51 0.19(fracture)
A tensile test was performed on a metal specimen with a diameter of 1/2 inch and a gage length (the length over which the elongation is meas- ured) of 4 inches. The data were plotted on a load-displacement graph, P vs. AL. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/AL = 1392 kips/in. What is the modulus of elasticity? BI
5. The following data were collected from a standard 0.505-in.-diameter test specimen of a copper alloy (initial length lo= 2.0 in.). After fracture, the total length was 3.014 in. and the diameter was 0.374 in. Load (Ib) Al (in.) 00000 3,000 6,000 0.00167 0.00333 7,500 0.00417 9,000 10,500 0.0090 0.040 12,000 0.26 12,400 11,400 0.50 (maximum load) 1.02 (fracture) a) Plot the data as engineering stress versus engineering strain. b) Compute the modulus of elasticity. c) Determine the yield strength at a strain offset of 0.002. d) Determine the tensile strength of this alloy. e) What is the approximate ductility, in percent elongation? f) Compute the modulus of resilience. g) Compute from the data and plot true stress versus true strain diagram.
Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Determine the true stress (in MPa) at yield point. - Determine the true stress (in MPa) at point of ultimate strength. - Determine the true stress (in MPa) at fracture point. - Determine the true strain (in mm/mm) at yield point. (Use at least five decimal units) - Determine the true strain (in mm/mm) at point of ultimate strength. (Use at least five decimal units) - Determine the true strain (in mm/mm) at fracture point. (Use at least five decimal units)
Question Following experimental data are obtained from tensile test of a rectangular test specimen with original thickness of 2,5 mm, gauge width of 24 mm and gauge length of 101 mm: Load (N) Elongation (mm) 0 0 24372 0,183 23008 0,315 28357 5,777 35517 12,315 27555 17,978 23750 23,865 Based on the information above; draw stress-strain diagram of the material and answer the following questions. - Calculate the yield strength (in MPa) of the material. - Calculate the percent elongation of the specimen at yield point. (Use at least five decimal units) - Calculate the stiffness (in MPa) of the specimen material. - Calculate the ultimate strength (in MPa) of the material. - Calculate the percent elongation of the specimen at point of ultimate strength.
Load (N) Elongation (mm) In a tensile test of stainless steel, the following data were obtained: 7,200 11,250 13,500 16,200 18,900 20,200 20,700 13,200 24.90 0.0 0.505 2.03 5.08 10.16 15.24 21.80 The dimensions of the cylindrical specimen were initial length L₁= 50.8 mm and initial area A₁ = 35.8 mm² and the area at fracture was Ar = 10.0 mm². Plot the stress-strain diagram and determine the following: a) Modulus of elasticity b) The yield strength at a strain offset of 0.002 c) Ultimate strength d) Fracture strength
Question A cylindrical specimen of metal having a diameter of 12.88 mm and a gauge length of 63.50 mm is tested using a tensile testing machine. The elongation measurement are recorded in Table 3. nPlot the stress-strain curve on the graph paper provided based on data in Table 3 Based on the stress-strain curved plotted in (i): Compute the modulus of elasticity Determine the yield strength at a strain offset of 0.002. Determine the tensile strength Determine the ductility in percent elongation and percent area reduction Table 3: Load-elongation readings for a metal specimen Jadual 3: Bacaan beban pemanjangan untuk statu spesimen logam) Load (N) Elongation (mm) 1380 0.03 2780 0.06 5630 0.12 7430 0.2 8140 0.25 9870 0.64 12850 1.91 14100 3.18 14340 4.45 13830 5.72 12500 6.99 Fracture