A tennis ball of mass 57.0 g is held just above a basketball of mass 608 g. With their centers vertically aligned, both balls are released from rest at the same time, to fall through a distance of 1.36 m, as shown in the figure below. (a) Find the magnitude of the downward velocity with which the basketball reaches the ground. (b) Assume that an elastic collision with the ground instantaneously reverses the velocity of the basketball while the tennis ball is still moving down. Next, the two balls meet in an elastic collision. To what height does the tennis ball rebound? Step 1 (a) When released, both balls start from rest and fall freely under the influence of gravity for 1.36 m before the basketball touches the ground. Their downward speed just before the basketball hits the ground is found from Voy - 2a Ay. In this problem we have that vy is the speed at impact with the ground of the basketball v. Solving for v; from the equation above, we have Vy m/s. V₁ = V 0 + 2(-9.80 m/s²) + 2a Ay = Voy n/s²)(- Note that both the acceleration due to gravity and the vertical displacement through which the balls fall are negative.
A tennis ball of mass 57.0 g is held just above a basketball of mass 608 g. With their centers vertically aligned, both balls are released from rest at the same time, to fall through a distance of 1.36 m, as shown in the figure below. (a) Find the magnitude of the downward velocity with which the basketball reaches the ground. (b) Assume that an elastic collision with the ground instantaneously reverses the velocity of the basketball while the tennis ball is still moving down. Next, the two balls meet in an elastic collision. To what height does the tennis ball rebound? Step 1 (a) When released, both balls start from rest and fall freely under the influence of gravity for 1.36 m before the basketball touches the ground. Their downward speed just before the basketball hits the ground is found from Voy - 2a Ay. In this problem we have that vy is the speed at impact with the ground of the basketball v. Solving for v; from the equation above, we have Vy m/s. V₁ = V 0 + 2(-9.80 m/s²) + 2a Ay = Voy n/s²)(- Note that both the acceleration due to gravity and the vertical displacement through which the balls fall are negative.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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