A ballistic pendulum is a simple, but practical, device that can be used to measure the speed of a bullet. The pendulum consists of a block of wood with mass 4.30 kg, at the end of a thin wire so that the center of the block is 85.6 cm below the top of the wire. With the block at rest and the wire vertical, a bullet of mass 29.0 grams is fired at the block. It embeds in the block and causes the block to swing so that it momentarily comes to rest when the wire makes an angle of 35.80 with the vertical. Find the initial speed, in m/s, of the bullet.

The pendulum apparatus in the video has a total mass of 578 grams. The pendulum rod has a small mass of 20 grams so you can treat all the mass of the pendulum as if it were hanging at the end which is called the “bob”. The mass of the rod should be taken into account in determining the center of mass of the apparatus which is 71.3 cm (not the length of the pendulum). A marble which hass a mass of 10 g is fired at the pendulum bob which has clay on it which allows the marble to stick to it.   Derive a formula for measuring the velocity of the marble (vm) as a function of the mass of the marble mm, the mass of the marble/bob mmb and the velocity of the marble and bob vmb using the conservation of momentum.

A large block of mass 3.80 kg slides on a frictionless table and collides head-on with a small block of mass 2.50 kg. After the collision both blocks move in the same direction as the original motion of the large block, and fall off the edge of the table. The small block hits the floor at a point 2.18 meters horizontally from the edge of the table, while the large block hits the floor at a point 1.38 meters horizontally from the edge of the table. The top of the table is 1.10 m above the floor. Find the speed, in m/s, of the large block before the collision.

In a ballistic pendulum experiment, a small marble is fired into a cup attached to the end of a pendulum. If the mass of the marble is 0.0235 kg and the mass of the pendulum is 0.250 kg, how high h will the pendulum swing if the marble has an initial speed of 5.65 m/s? Assume that the mass of the pendulum is concentrated at its end so that linear momentum is conserved during this collision. h = m

In the figure, projectile particle 1 is an alpha particle and target particle 2 is an oxygen nucleus. The alpha particle is scattered at angle 0₁ = 63.1° and the oxygen nucleus recoils with speed 1.60 × 105 m/s and at angle 0₂ = 52.0°. In atomic mass units, the mass of the alpha particle is 4.00 u and the mass of the oxygen nucleus is 16.0 u. What are the (a) final and (b) initial speeds of the alpha particle? (a) Number (b) Number i m₁ Vli Units Units mg vaf x

A steel ball of mass 0.600 kg is fastened to a cord that is 80.0 cm long and fixed at the far end. The ball is then released when the cord is horizontal. At the bottom of its path, the ball strikes a 3.00 kg steel block initially at rest on a frictionless surface. The collision is elastic. (a) Find the speed of the ball just after collision. (No Response) m/s (b) Find the speed of the block just after collision. (No Response) m/s

A steel ball of mass 0.440 kg is fastened to a cord that is 80.0 cm long and fixed at the far end. The ball is then released when the cord is horizontal, as shown in the figure. At the bottom of its path, the ball strikes a 3.10 kg steel block initially at rest on a frictionless surface. The collision is elastic. Find (a) the speed of the ball and (b) the speed of the block, both just after the collision. (a) Number i (b) Number Unit Unit

In a ballistic pendulum experiment, a small marble is fired into a cup attached to the end of a pendulum. If the mass of the marble is 0.0285 kg and the mass of the pendulum is 0.250 kg, how high h will the pendulum swing if the marble has an initial speed of 5.85 m/s? Assume that the mass of the pendulum is concentrated at its end so that linear momentum is conserved during this collision. h = m

You fire an old rifle at a block of wood. The mass of the block of wood is 231 g and it dimensions are 10.2 cm × 10.2 cm × 3.16 cm. The bullet has a mass of 24.6 grams. Assume no air resistance and that the collision is perfectly inelastic. The velocity of the bullet is 22: m/s right before it hits the block. Assume no mass is lost when the two objects collide. 10.2 cm 1. The distance the bullet hits from the center of mass is 3.4 cm COM. How high up does the block travel? cm 2. What is the rotation rate (rev/s) of the block & bullet system directly after impact? 3.16

Two 1.9 kg bodies, A and B, collide. The velocities before the collision are v A= (14î + 34 j) m/s and v = (-15î + 9.0j) m/s. After the collision, v = (-7.oî + 16 j) m/s. (a) What is the final velocity of B? m/s (b) What is the change in the total kinetic energy (including sign)? 121.69 J The net external force on the two particle system is zero; thus, the net momentum of the system cannot change. The net momentum along the x axis before the collision must equal that after the collision. Same for the y axis. Use the definition of kinetic energy to find the total K before the collision and the total K after.