A survey of 80 recent fatal traffic accidents showed that 50 were alcohol-related.  Find the 84% confidence interval for the percentage of all fatal traffic accidents that are alcohol-related

Q: Find the critical value for the population mean if there are 756 cats in a sample and you want a 91%…

A:

Q: A survey of 540 depressed shoppers found at 32% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: In a random sample of 100 customers, the items that customers purchased were tracked. It was found…

A: Given,sample size(n)=100sample proportion(p^)=0.171-p^=1-0.17=0.83α=1-0.90=0.1α2=0.05Z0.05=1.645

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: confidence interval for the proportion of unemployed adults who have been unemployed for more than…

A: Here given  In a survey of 532 unemployed adults, 225 said that they had been unemployed for more…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Sample taken for ages 19 to 25 2253 men and 2629 women random sample In which 986 men and 923 women…

Q: In a survey of 1005 adults 526 stated construct a 95% confidence interval

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Q: Of 127 randomly selected adults, 31 were found to have high blood pressure. Construct a 95%…

A: Given that, Of 127 randomly selected adults, 31 were found to have high blood pressure.  X = 31 N =…

Q: A survey of 45,535 adults showed that 20,901 were very concerned abut climate change. What is the…

A:

Q: Out of 180 randomly selected adults in the United States who were surveyed, 81 exercise on a regular…

A:

Q: According to a report on consumer fraud and identity theft, Indiana had 1671 complaints of identity…

A:

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A: Given,n=1037x=643p^=xnp^=6431037=0.6201-p^=1-0.620=0.380α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a survey of 2896 adults, 1441 say they have started paying bills online in the last year.…

A: Given data X=1441 n=2896

Q: A random variance survey of 495 adults found that 59 had diabetes. which of the following is a 98%…

A:

Q: A survey of 45,535 adults showed that 20,901 were very concerned abut climate change. What is the…

A: It is given asFavourable cases, x = 20901Sample size, n = 45535Confidence level = 99%

Q: In a random sample of 500 Americans, 25% indicated that they have a cat for a pet. Estimate with 97%…

A:

Q: In a random sample of 500 Americans, 50% indicated that they have a cat for a pet. Estimate with 95%…

A: Given information

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: A recent study showed that among 725 randomly selected subjects who completed 4 years of college,…

A: We have given that,  Favorable cases (X) = 139 and Sample size    (n) = 725 Then,  We will find 95%…

Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: a survey of 3409 adults, 1445 say they have started paying bills online in the last year.  Construct…

A: The confidence interval = 99%The faovarble cases [x] = 1445The sample size [n] = 3409

Q: n a randomly selected group of 750 automobile deaths, 240 were alcohol related. Construct a 95%…

A: Given that,  x = 240, n = 750 The value of sample proportion is,

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: In a survey of 3235 adults 1499 say they have started paying bills online in the last year. A 99%…

A: Solution: Let X be the number of adults say they have started paying bills online in the last year…

Q: A survey of 300 women shoppers found that 17% of them shop on impulse. What is the 80% confidence…

A: From the provided information,A survey of 300 women shoppers found that 17% of them shop on impulse.…

Q: A sample of 400 homeowners includes 124 that expect their home to increase in value in the next…

A: Margin of error: ME=Zα/2 * √p̂(1-p̂)/n

Q: 82 adults selected randomly from one town, 66 have health insurance. Find a 90% confidence interval…

A:

Q: A U.S. Travel Data Center survey of 500 adults found that 195 said they would take more vacations…

A: Solution: Let X be the number of adults who said that they will travel more this year and n be…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: In a sample of 1901 patients who underwent a certain type of surgery, 22% experienced complications.…

A:

Q: 9. A survey of 280 homeless persons showed that 63 were veterans. Construct a 90% confidence…

A: In a survey of 280 homeless persons showed that 63 were veterans.

Q: In a randomly selected group of 650 automobile deaths, 180 were alcohol-related. Construct a 95%…

A:

Q: Out of 157 randomly selected adults in the United States who were surveyed, 77 exercise on a regular…

A:

Q: As health insurance costs and the number of disabled employees increase, more companies are firing…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: From a lake, an unknown proportion of fish have been tagged.  You collect a sample of 100 fish taken…

A:

Q: In a random sample of 100 drivers, 80 were using seat belts while driving. Construct a 95%…

A:

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: A research poll of 1501 adults showed that 1051 of respondents believe in global warming. Find a 98%…

A:

Q: Construct a 90% confidence interval for the mean when x̅=50 and there are 31 observations. Suppose…

A:

Q: An actuary is interested in estimating the proportion of young adults who plan to have children…

A: We need to construct the 99% confidence interval for the population proportion. We have been…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.