MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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Consider that, µA, µB, µC and µD define the mean lifespan of sunscreen A, B, C, and D, respectively.
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- A popular, nationwide standardized test taken by high-school juniors and Españ seniors may or may not measure academic potential, but we can nonetheless attempt to predict performance in college from performance on this test. We have chosen a random sample of students just finishing their first year of college, and for each student we've recorded her score on this standardized test (from 400 to 1600) and her grade point average (from o to 4) for her first year in college. The data are shown below, with x denoting the score on the standardized test andy denoting the first-year college grade point average. The least-squares regression line for these data is 1.1239+0.0015x. This line is shown in the scatter plot below. Standardized test score, .x 1360 1100 790 1280 890 Grade point average, y 3.77 2.28 2.35 2.91 2.64 2.22 3.18 3.34 2.36 3.30 3.02 2.88 860 1400 1510 1000 1250 1060 1210 1020 940 1510 Send data to calculator ✓ Send data to Excel 3.07 2.29 3.01 Grade point average, 34- 324 900…arrow_forwardA local ice cream shop collects data on the temperature of the day and how many ice cream cones were sold that day. What type of data was collected? Bivariate and Quantitative Bivariate and Categorical Univariate and Quantitative Univariate and Categoricalarrow_forwardLDL - low density lipoprotien - cholesterol is considered the bad cholesterol. A pharmaceutical company conducts a clinical trial on people with high levels of LDL cholesterol. The trial involves a random sample of n = 13 persons who have high levels of LDL. Each person has their LDL level measured prior to the beginning of the drug trial. Each person is then to take a new drug that is believed to lower ones LDL levels. After a period of 4-weeks, the LDL level of each person is measured again. The difference between the initial LDL level and the LDL-level four weeks after taking the drug is then computed. -0.44, -0.63,-0.73, 0.38, -0.21, 0.05, -0.53, -1.02, -0.3, -0.32, -0.06, -0.4, -0.63 Data from the sample, are saved in the Download .csv file. Assuming the difference in the LDL-levels is Normally distributed, find a 94% confidence interval for μ, the mean difference in the LDL-level of a person after taking the drug for four weeks. Use at least four decimals for your lower and upper…arrow_forward
- I ONLY NEED HELP ON D and E thank youarrow_forwardman loves, as everyone should, to collect and analyze statistical information. He wishes to find a relationship between how many hours students study and how they do on their statistics tests. He takes a random sample of 16 students at Ideal U., asks how many hours they studied for a university-wide stat test and how they did on the test, enters the data into a computer for analysis and presents the results below. ANALYSIS OF HOURS AND GRADES (n = 16): Descriptive Statistics: HOURS GRADES Mean: 4.2 75.8 Mode: 5.0 79.0 St. Dev: 2.3 10.1 Quartiles: Q0 2.0 34.0 Q1 3.2 53.7 Q2 4.7 78.5 Q3 6.3 86.9 Q4 9.0 97.0 Regression Analysis: Reg. Eq. is: GRADE = 16.9 + 9.025*HOURS Rsquared = .985 std error = 0.027 F = 8.52 p = .018 What problem might there be in using the regression model to predict what grade a student might get if they studied 10 hours? a. The predicted grade for 10 hours is more than 100, which is impossible. b. The value of 10…arrow_forwardi need this, the t statistic, and p valuearrow_forward
- We collected data for 300 people at a movie theater. For every person, we know what genre of movie they saw and whether or not they bought snacks.(we would expect 100% of people to bring snacks) Here are the results Type of Movie Snacks No Snacks Action 26 34 Comedy 47 23 Family 90 30 Horror 30 20 chi square test of independencearrow_forwardRandom collections of nine different solutions of a calcium compound were given to two laboratories, A and B. Each laboratory measured the calcium content (in mmol per liter) and reported the results. The data are paired by calcium compound. Compound Lab A (x) Lab B (y) 1 2 3 4 7 9. 9.36 14.80 8.79 11.33 10.56 15.61 13.70 12.03 11.56 9.14 14.74 8.67 11.51 10.63 15.59 13.74 12.22 11.56 (a) Rank-order the data using 1 for the lowest calcium reading. Make a table of ranks to be used in a Spearman rank correlation test. Compound Lab A (x) Lab B (y) d = x – y d2 1 3 4 7 8 Ed? Compute the sample test statistic. (Round your answer to three decimal places.) IIarrow_forward
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