A student weighs out a 3.48 g sample of manganese(II) chloride, transfers it to a 125 mL volumetric flask, adds enough water to dissolve it and then adds water to the 125 mL tic mark. What is the molarity of MnCl, in the resulting solution?

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
### Determining the Molarity of a Manganese(II) Chloride Solution

A student weighs out a 3.48 g sample of manganese(II) chloride, transfers it to a 125 mL volumetric flask, adds enough water to dissolve it, and then adds water to the 125 mL tic mark.

**Problem:**
What is the molarity of MnCl₂ in the resulting solution?

**Solution:**

To find the molarity, we need to follow these steps:

1. **Calculate the molar mass of MnCl₂:**
   - Manganese (Mn): Atomic mass = 54.94 g/mol
   - Chlorine (Cl): Atomic mass = 35.45 g/mol (since there are two Cl atoms, multiply by 2)

   Molar mass of MnCl₂ = 54.94 g/mol + (2 × 35.45 g/mol) = 54.94 g/mol + 70.90 g/mol = 125.84 g/mol

2. **Convert grams of MnCl₂ to moles:**
   \[\text{moles of MnCl₂} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} = \frac{3.48 \, \text{g}}{125.84 \, \text{g/mol}} = 0.02765 \, \text{mol}\]

3. **Convert the volume from mL to L:**
   \[125 \, \text{mL} = 0.125 \, \text{L}\]

4. **Calculate the molarity (M):**
   \[\text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} = \frac{0.02765 \, \text{mol}}{0.125 \, \text{L}} = 0.2212 \, \text{M}\]

Therefore, the molarity of MnCl₂ in the resulting solution is **0.2212 M**.

**Box for Answer:**
\[ \boxed{0.2212 \, \text{M}} \]

This question can be useful for students who want to understand the process of calculating the molarity of a solution from a given mass of solute and the final volume of solution.
Transcribed Image Text:### Determining the Molarity of a Manganese(II) Chloride Solution A student weighs out a 3.48 g sample of manganese(II) chloride, transfers it to a 125 mL volumetric flask, adds enough water to dissolve it, and then adds water to the 125 mL tic mark. **Problem:** What is the molarity of MnCl₂ in the resulting solution? **Solution:** To find the molarity, we need to follow these steps: 1. **Calculate the molar mass of MnCl₂:** - Manganese (Mn): Atomic mass = 54.94 g/mol - Chlorine (Cl): Atomic mass = 35.45 g/mol (since there are two Cl atoms, multiply by 2) Molar mass of MnCl₂ = 54.94 g/mol + (2 × 35.45 g/mol) = 54.94 g/mol + 70.90 g/mol = 125.84 g/mol 2. **Convert grams of MnCl₂ to moles:** \[\text{moles of MnCl₂} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} = \frac{3.48 \, \text{g}}{125.84 \, \text{g/mol}} = 0.02765 \, \text{mol}\] 3. **Convert the volume from mL to L:** \[125 \, \text{mL} = 0.125 \, \text{L}\] 4. **Calculate the molarity (M):** \[\text{Molarity (M)} = \frac{\text{moles of solute}}{\text{liters of solution}} = \frac{0.02765 \, \text{mol}}{0.125 \, \text{L}} = 0.2212 \, \text{M}\] Therefore, the molarity of MnCl₂ in the resulting solution is **0.2212 M**. **Box for Answer:** \[ \boxed{0.2212 \, \text{M}} \] This question can be useful for students who want to understand the process of calculating the molarity of a solution from a given mass of solute and the final volume of solution.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Basics of Titrimetric Analysis
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY