A student of weight 667 N rides a steadily 45 SSM ILW rotating Ferris wheel (the student sits upright). At the highest point, the magnitude of the normal force Fy on the student from the seat is 556 N. (a) Does the student feel "light" or "heavy" there? (b) What is the magnitude of Fy at the lowest point? If the wheel's speed is doubled, what is the magnitude Fy at the (c) high- est and (d) lowest point?

A body of mass m is attracted toward a 11.1 kg mass, 31.5 cm away, with a force of magnitude 6.60 10-8 N. Find m. can you also add the units!

An astronaut takes a set of scales to do some measurements while travelling. Before leaving earth, the astronaut stands on the scales and they read "75 kg". Determine what the readings would be in the following circumstances. (You will first need to decide what the scales physically relate to). (a) On the moon where gravity is 1.6 m/s² nds o t tant (b) Near the surface of Jupiter where gravity is 26 m/s? the Tian (of mas m basks in the sen on a dop Which ofe The de of the no fore (c) In the spaceship travelling in between planets the ig lore ain .ont fom an action The direction of the o l foree acting on the ands verically upwants 4 The normal frce tg on he wegh

A small sphere of mass 2.50 g is released from rest in a large vessel filled with oil, where it experiences a resistive force proportional to its speed. The sphere reaches a terminal speed of 4.00 cm/s. Determine the time constant, and the time at which the sphere reaches 75.0% of its terminal speed.

Write Newton's laws for a static system (1) EF, = mg sin 0 – µ̟n = 0 in component form. The gravity force has two components. (2) EF, = n - mg cos 0 = 0 Rearrange Equation (2) to get an n = mg cos e expression for the normal force n. Substitute the expression for n into EF, = mg sin 0 – µ̟mgcos 0 = 0 → tan 0 =µ, Equation (1) and solve for tan 0. Apply the inverse tangent function to tan 0 = 0.350 → 0 = tan 1 (0.350) = 19.3° get the answer. LEARN MORE REMARKS It's interesting that the final result depends only on the coefficient of static friction. Notice also how similar Equations (1) and (2) are to the equations developed in previous problems. Recognizing such patterns is key to solving problems successfully. QUESTION A larger static friction constant would result in a: (Select all that apply.) O larger component of normal force at the maximum angle. O larger component of gravitational force along the ramp at the maximum angle. smaller component of gravitational force along the ramp…

In designing circular rides for amusement parks, mechanical engineers must consider how small variations in certain parameters can alter the net force on a passenger. Consider a passenger of mass m riding around a horizontal circle of radius r at speed v.What is the variation dF in the net force magnitude for (a) a variation dr in the radius with v held constant, (b) a variation dv in the speed with r held constant, and (c) a variation dT in the period with r held constant?

Crates A and B have equal mass. Crate A is at rest on an incline that makes and angle of theta = 22.22 degrees horizontal, while crate B is at rest on a horizontal surface.   Write an expression for the ratio fo the normal forces, A to B in terms of theta?

Two boxes (Box A = 9.7 kg and Box B = 5.4 kg) are connected by acord running over a pulley. The coefficient of kinetic friction betweenbox A and the table is 0.18. We ignore the mass of the cord and pulleyand any friction in the pulley, which means we can assume that a forceapplied to one end of the cord will have the same magnitude at theother end. We wish to find the tension of the cord while accelerating (inN), assuming the cord doesn’t stretch. As box B moves down, box Amoves to the right. Hint: Solve for the acceleration of the system first.

A horizontal force with magnitude of 52.0N on a box and produces acceleration with magnitude 3.60 m/s^2. What is the mass of the box?

1F=10k 30 5=12k 5=18k Calculate the Fx and Fy components of all the the forces and determine the resultant force. 券