A student dissolves 11.9 g of ammonium nitrate (NH4NO3) in 200. g of water in a well-insulated open cup. He then observes the temperature of the water f from 22.0 °C to 16.5 °C over the course of 7.6 minutes. Use this data, and any information you need from the ALEKS Data resource, to answer the questions below about this reaction: NH4NO3 (s) NH(aq) + NO3 (aq) You can make any reasonable assumptions about the physical properties of the solution. Be sure answers you calculate using measured data are rounded to significant digits. Note for advanced students: it's possible the student did not do the experiment carefully, and the values you calculate may not be the same as the known and published values for this reaction. Is this reaction exothermic, endothermic, or neither? If you said the reaction was exothermic or endothermic, calculate the amount of heat that was released or absorbed by the reaction in this case. Calculate the reaction enthalpy AHxn per mole of NH4NO3. O exothermic endothermic Oneither KJ kJ 0- mol 0x10 X

Ethylene (C2H4) plays an important role in the ripening of certain fruits and vegetables. It is sometimes supplemented under controlled conditions at produce—processing facilities but is also produced naturally by many fruit-bearing plants.  Although the actual process by which plants produce ethylene is a complex one, imagine that it is produced by the simple breakdown of glucose according to the equation: C6H12O6 (s)  à 3 C2H4 (g) + 3 O2 (g)   Given S°= 212.1 J/molK, DG°= -910.56 kJ/mol and DH°= -1274.5 kJ/mol for C6H12O6 (s).   a.) Determine the sign of DS° for the reaction. b.) Calculate DS° for the reaction. c.) Using the tabulated DG° values in the appendix, calculate DG° for the reaction. d.) Above what temperature (in °C) is the reaction spontaneous? Hint: you will first have to calculate DH° using tabulated values.

A student dissolves 12.3 g of potassium chloride (KCI)in 250. g of water in a well-insulated open cup. He then observes the temperature of the water fall from 22.0 °C to 19.6 °C over the course of 5.9 minutes. Use this data, and any information you need from the ALEKS Data resource, to answer the questions below about this reaction: olo Ar KCI(s) K* (aq) + CI (aq) You can make any reasonable assumptions about the physical properties of the solution. Be sure answers you calculate using measured data are rounded to the correct number of significant digits. Note for advanced students: it's possible the student did not do the experiment carefully, and the values you calculate may not be the same as the known and published values for this reaction. exothermic Is this reaction exothermic, endothermic, or neither? endothermic neither If you said the reaction was exothermic or endothermic, calculate the amount of heat that was released or absorbed by the reaction in this case. |kJ kJ Calculate…

Ammonia can be produced by the reaction of hydrogen gas and nitrogen gas, as shown below: N2(g) + 3H2(g) → 2NH3(g) Given that the standard free energy of formation of NH3 (g) is -104 kJ/mol at 298 K, calculate the equilibrium constant, K, at this temperature. To express an answer in exponential notation, use E to indicate the exponent. For example, 3.0 x 103 would be written, 3.0E3.

You add some of the white crystals to a small test tube filled with water. The water in the test tube was initially at room temperature (25˚C). Once the crystals were added and the tube was stirred, the temperature of the solution decreased to about 15˚C and all of the crystals dissolved. what is the change in Gibbs free energy (∆G) for this process?

Consider the reaction. 2 Fe,O, 4 Fe + 30, AHn = +824.2 kJ The formation of 84.0 g of Fe results in the absorption of 3.10 x 102 kJ of heat. the absorption of 17300 kJ heat. the absorption of 1240 kJ of heat. the release of 1240 kJ of heat. the release of 3.10 x 10² kJ of heat. the release of 17300 kJ of heat. G Search or type URL

Calculate the enthalpy of decomposing hydrogen iodide to produce hydrogen and iodine.                                          2HI(g) →  I2(s) + H2(g)   I2(s) → I2(g)                                  ΔH⁰ = 124.8 kJ/mol I2(g) + H2(g) → 2HI(g)                          ΔH⁰ = - 73.0 kJ/mol