Example: 2A Steel wire hangs vertically under its weight. What isthe greatest length it can have if the allowable tensileDensity of steel y=80stresso, =200 MPa?kN/m3.(ans:-2500 m)Solution:0, =200 MPa= 200*103 kN/m² :Ly=80 kN/m³.Wt. of wire P=(t/4)(D²)(L)* yc/s area of wire A=(t/4)*D²Of = PIAsolving above eq. L=2500m

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A Steel wire hangs vertically under its weight. What is the greatest length it can have if the allowable tensile stress o, =200 kN/m3.(ans:-2500 m) Solution: MPa? Density of steel y=80 O; =200 MPa= 200*103 kN/m² ; L y=80 kN/m³. Wt. of wire P=(Tt/4)(D²)(L)* y c/s area of wire A=(t/4)*D² Of = PIA solving above eq. L=2500m

A Steel wire hangs vertically under its weight. What is the greatest length it can have if the allowable tensile stress o, =200 kN/m3.(ans:-2500 m) Solution: MPa? Density of steel y=80 O; =200 MPa= 200103 kN/m² ; L y=80 kN/m³. Wt. of wire P=(Tt/4)(D²)(L) y c/s area of wire A=(t/4)*D² Of = PIA solving above eq. L=2500m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Principles of Seepage

In hydrology, when water flows down in a pore or crack of unsaturated soil due to gravity, the deep layer of soil is called seepage. It is the slow movement of water in the soil layer. Seepage is mainly found near hydraulic structures and is responsible for the stability of earthen-type hydraulic structures.

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Example: 2
A Steel wire hangs vertically under its weight. What is
the greatest length it can have if the allowable tensile
Density of steel y=80
stress
o, =200 MPa?
kN/m3.(ans:-2500 m)
Solution:
0, =200 MPa= 200*103 kN/m² :
L
y=80 kN/m³.
Wt. of wire P=(t/4)(D²)(L)* y
c/s area of wire A=(t/4)*D²
Of = PIA
solving above eq. L=2500m

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