A steel tube with the cross section shown is 6 ft long and has a wall thickness of 0.12 in. Determine: (a) If the allowable shear stress is 8000 psi, determine the largest torque that can be applied safely to the tube. (b) Compute the corresponding angle of twist. Use G = 12 x 10^6 psi for steel. Figure: 2 in. 2 in. – 2 in.→2 in. →

A metal shaft ABCD with variable cross-section is subjected to three external torques (T₁=28 kip- in, T2=8 kip-in, and T3=10 kip-in) as shown in the figure below. Each torque is acting at the locations marked with circular points along the shaft. Note that a 16-inch long segment of the shaft at the free end (right) has a 1-inch diameter bore. The dimensions (lengths and diameters) of the shaft are given in the figure. Assume deformation is linear elastic and take G=12×106 psi. D [3" 16"- X C T₁ 2" -32"- T₂ 1" diam. bore B -16"- A T3 the bar has a uniform diameter d along its full length, but external torques remain the same and are applied at the same locations. If the failure shear stress for the material is equal to Tfail = 10 ksi, and the factor of safety is equal to 2, determine the required (uniform) diameter d for the bar. Assume that the bar is solid for its entire length.

An irregular shaped hollow tube, with the dimensions shown in figure below, is subjected to a torque of 2.5 kN m. If the tube is fabricated from steel and is 4 m long, determine the maximum value of the average shearing stress and the angle of twist of the tube. Note that the wall thickness of vertical sides is 6 mm and the thickness of the horizontal sides is 5 mm. * Assume the following values: • L₁= 44 mm • L₂ = 50 mm • L3= 88 mm • LA = 25 mm Taug ++ S+ O - L₁ number (rtol-0.01, atol-1e-05) number (rtol-0.01, atol-1e-05) L3 MPa L2

Please help. This problem involves torsional stress and strain. Thank you.

The shaft in Figure below consists of a 3-in. -diameter aluminum segment that is rigidly joined to a 2-in. -diameter steel segment. The ends of the shaft are attached to rigid supports, Calculate the maximum shear stress developed in each segment when the torque T= 10 kip.in is applied. Use G = 4×106 psi for aluminum and G = 12×106 psi for steel. Aluminum 3-in. diameter 6 ft T Steel 2-in. diameter 3 ft

The following data relate to a compound impulse turbine having two rows of moving blades and one row of fixed blades in between them. Steam velocity coming out of nozzle = 450 m/sec., Nozzle angle 15°, Moving blades tip discharge angles = 30°, Fixed blade discharge angle = 20°, Friction loss in each blade rows = 10% of the relative velocity. Find the blade velocity, blade efficiency and specific steam consumption for turbine.

(2) The shaft consists of a 3-in diameter aluminum segment that is rigidly joined to a 2-in diameter steel segment. The ends of the shaft are attached to rigid supports, Calculate the angle of twist developed at the interface of the two segments when the torque T = 50 kip in is applied. Use G = 4×106 psi for aluminum and G = 12×106 psi for steel. | Aluminum 3-in. diameter 6 ft T Steel 2-in. diameter 3 ft D

The shaft consists of a 3-in diameter aluminum segment that is rigidly joined to a 2-in diameter steel segment. The ends of the shaft are attached to rigid supports, Calculate the angle of twist developed at the interface of the two segments when the torque T = 50 kip٠in is applied. Use G = 4×106  psi for aluminum and G = 12×106 psi for steel.